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3 years ago

Please help and show work I’m begging

Mathematics

1 answer:

mixas84 [53]3 years ago

5 0

13. Pick a point and see which formula works.
Ay = -4, A'y = 7. Only the formula of selection D makes that translation.

14. Use the compound interest formula A = P*(1 +r/n)^(nt).
..1500*1.015^80 = 4935.99, matching selection C

15. The lid has a perimeter of 90", so the area of the sides is
.. 90" * 24" = 2160 in^2
The area of the lid is
.. 30" * 15" = 450 in^2

The gray area is (2160 -450) in^2 = 1710 in^2 larger, corresponding to selection C.

16. The only formula that maps (7, -1) to (21, -3) is that of selection D.

_____
The middle two problems are the only ones that require you to have prior knowledge. The others could be answered simply by seeing if the answers work.

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Waitonehundredmorepoints

Veseljchak [2.6K]

Answer:

She Jen djzksndhdi

Step-by-step explanation:

7 0

3 years ago

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Consider the following region R and the vector field F. a. Compute the two-dimensional curl of the vector field. b. Evaluate bo

Shalnov [3]

Looks like we're given

$\vec F(x,y)=\langle-x,-y\rangle$

which in three dimensions could be expressed as

$\vec F(x,y)=\langle-x,-y,0\rangle$

and this has curl

$\mathrm{curl}\vec F=\langle0_y-(-y)_z,-(0_x-(-x)_z),(-y)_x-(-x)_y\rangle=\langle0,0,0\rangle$

which confirms the two-dimensional curl is 0.

It also looks like the region $R$ is the disk $x^2+y^2\le5$ . Green's theorem says the integral of $\vec F$ along the boundary of $R$ is equal to the integral of the two-dimensional curl of $\vec F$ over the interior of $R$ :

$\displaystyle\int_{\partial R}\vec F\cdot\mathrm d\vec r=\iint_R\mathrm{curl}\vec F\,\mathrm dA$

which we know to be 0, since the curl itself is 0. To verify this, we can parameterize the boundary of $R$ by

$\vec r(t)=\langle\sqrt5\cos t,\sqrt5\sin t\rangle\implies\vec r'(t)=\langle-\sqrt5\sin t,\sqrt5\cos t\rangle$

$\implies\mathrm d\vec r=\vec r'(t)\,\mathrm dt=\sqrt5\langle-\sin t,\cos t\rangle\,\mathrm dt$

with $0\le t\le2\pi$ . Then

$\displaystyle\int_{\partial R}\vec F\cdot\mathrm d\vec r=\int_0^{2\pi}\langle-\sqrt5\cos t,-\sqrt5\sin t\rangle\cdot\langle-\sqrt5\sin t,\sqrt5\cos t\rangle\,\mathrm dt$

$=\displaystyle5\int_0^{2\pi}(\sin t\cos t-\sin t\cos t)\,\mathrm dt=0$

7 0

3 years ago

What is th e best estimate for 5 1/9 - 1 5/6

valentinak56 [21]

5 1/9 - 5 5/6 is 3.27, if you want it rounded to the nearest whole number then that would by 3

have a nice day :)

3 0

3 years ago

What is the value of x? 6x−2(x 4)=12

jonny [76]

Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored

Equation at the end of step 2 : 6x2 - x - 4 = 0 ((2•3x2) - x) - 4 = 0 Step 2 :Trying to factor by splitting the middle term

2.1 Factoring 6x2-x-4

The first term is, 6x2 its coefficient is 6 .
The middle term is, -x its coefficient is -1 .
The last term, "the constant", is -4 

Step-1 : Multiply the coefficient of the first term by the constant 6 • -4 = -24

Step-2 : Find two factors of -24 whose sum equals the coefficient of the middle term, which is -1 .

-24 + 1 = -23 -12 + 2 = -10 -8 + 3 = -5 -6 + 4 = -2 -4 + 6 = 2 -3 + 8 = 5 -2 + 12 = 10 -1 + 24 = 23

Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored

Equation at the end of step 2 : 6x2 - x - 4 = 0

3 0

3 years ago

Simplify-2+3(1-4)-2 one answer

Murrr4er [49]

Your answer would be -13 !!!

4 0

2 years ago

Read 2 more answers