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2 years ago

Golf ball sized basketballs are often packed in cylindrical canisters

SAT

1 answer:

viktelen [127]2 years ago

6 0

The correct statement about the circumference (C) and the height (h) is gotten as; C > h

<h3>How to find the circumference of the cylinder?</h3>

The formula for circumference of a cylinder is;

C = 2πr

Now, we are not given the radius of the cylinder but we are told that there are 3 balls that fit perfectly into the cylindrical canister. Each having a diameter of 1.68 inches.

Thus;

Radius; r = d/2 = 1.68/2 = 0.84 inches

Height of cylinder will be;

h = 3d = 3 * 1.68

h = 5.04 inches

Circumference; C = 2π * 0.84 = 5.28 inches. Thus;

C > h

The complete question;

Golf ball size basketballs are often packed in cylindrical canisters. The diagram below shows three balls in a canister. Let C be the circumference of the canister and let H be the height of the canister. Assuming each ball has a diameter of 1.68 inches and the balls fit snugly in the canister, which of the following statements is correct?

Read more about Circumference at; brainly.com/question/2626028

#SPJ1

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A mouse runs along a baseboard in your house. The mouse's position as a function of time is given by x(t)=pt2+qt, with p = 0. 40

Gelneren [198K]

The average speed between t = 1.0 s and t = 4.0 s will be 2.1+0.3 which is 2.4m/s

<h3>Velocity function </h3>

Given the equation for the position of the mouse expressed as:

$x(t)=pt^2+qt\\$

The velocity of the particle is expressed as:

$v(t)=2pt+q$

Given that p = 0. 40 m/s and q = -1. 10 m/s, the equation will become:

$v(t)=2(0.4)t-1.10\\v(t)=0.8t - 1.10$

If the time is <em>t = 1.0 s, the velocity will be:</em>

$v(1) = 0.8 - 1.10\\v(1) = -0.3m/s$

Similarly if t = 4.0ssec, hence:

$v(4) = 3.2 - 1.10\\v(4) = 2.1m/s$

The average speed between t = 1.0 s and t = 4.0 s will be 2.1+0.3 which is 2.4m/s

<em>Learn more on</em><em> average speed </em><em>here: brainly.com/question/4931057</em>

Complete question

<em>A mouse runs along a baseboard in your house. The mouse's position as a function of time is given by x(t)=pt 2+qt, with p = 0.40 m/s2and q = -1.10 m/s . Determine the mouse's average speed between t = 1.0 s and t = 4.0 s. I have tried everything and the answer is not 0.40 m/s</em>

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