Base on the total area of the square garden and the number of plants planted on it, the area of the zucchini section is 15 feet²
<h3>How to find area of zucchini section?</h3>
Side Length of the square garden = 8 feet
Area of the garden = side length ²
= 8 feet × 8 feet 
= 64 feet²
Flower portion:
Side Length = 2 feet
Area of flower portion = side length ²
= 2 feet × 2 feet
= 4 feet²
Remaining space = Area of the garden - Area of flower portion
= 64 feet² - 4 feet²
= 60 feet²
Remaining space is divided into 4 equal sections
= 60 feet² / 4
= 15 feet²
Therefore,
Tomatoes section = 15 feet²
Onions section = 15 feet²
Zucchini section = 15 feet²
Pepper section = 15 feet²
Learn more about area of a square:
brainly.com/question/24487155
#SPJ1
 
        
             
        
        
        
Hi
We know that Area= length * width right?
So this is what we do.
Total area/length
25/54 / 5/9
You get the width to be 5/6
CHECK:
5/6*5/9=25/54
Hope this helps :)
        
             
        
        
        
64x^6 - 192x^5 + 240x^4 - 160x^3 + 60x^2 - 12x + 1
        
             
        
        
        
Answer:
{y≥1
,{y-x>0
Step-by-step explanation:
First of all you have to consider the shaded region. It is bound by two lines.
The first line is a solid line that cuts the y-axis at +1. it's equation is y = 1. since the shade region is on the upper side where y values increase, the unequivocally will be y≥1. notice that the sign ≥ is due to the solid line which indicates points on the solid line are part of the solution.
the second line is the broken line. it passes through the origin (0,0) and (1,1) any two points can be taken. the gradient is 1. m= (y1-y2)/(x1-x2) = (0-1)/(0-1)=(-1/-1)= 1. the equation of a straight line is
y=mx + c where m is gradient and c is the VA)ue of y as the line crosses the y axis ( y-intercept) which in this case is 0 at (0,0).so the equation will be y=1(x) + 0
 y=x if we subtract x from both sides we have
 y-x=0
since the shaded region is on the upper side as y-x increases the in equality will be
 y-x>0 notice since the line is broken it shall be just > not≥ because points on a broken line are not included in the shaded region.