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Bess [88]
3 years ago
6

Determine if the given differential equation is exact (e^2y-y cos xy)dx+(2xe^2 y-cos xy+2y)dy=0

Mathematics
1 answer:
rewona [7]3 years ago
7 0
\dfrac\partial{\partial y}\left[e^{2y}-y\cos xy\right]=2e^{2y}-\cos xy+xy\sin xy

\dfrac\partial{\partial x}\left[2xe^{2y}-y\cos xy+2y\right]=2e^{2y}+y\sin xy

The partial derivatives are not equal, so the equation is not exact.
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The inequality representation of the scenario is :

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Learn more : brainly.com/question/15748955

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