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4 years ago

Offering 15 points please help

Mathematics

1 answer:

mario62 [17]4 years ago

6 0

Answer:

(2x + 3)(x - 7)

Step-by-step explanation:

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Given: Quadrilaterals ABCD ~ EFGH , with measure of angle A = 47 degrees, measure of angle B = 39 degrees, and measure of angle

kaheart [24]

Answer:

The answer is below

Step-by-step explanation:

Two polygons are said to be congruent if they have the same size and shape that is their corresponding angles and sides are equal.

Hence since Quadrilaterals ABCD is congruent to EFGH, then their corresponding angles and sides are equal.

In quadrilateral ABCD:

∠A + ∠B + ∠C + ∠D = 360° (sum of angles in a quadrilateral)

Substituting:

47 + 39 + 112 + ∠D = 360

∠D + 198 = 360

∠D = 360 - 198

∠D = 162°

The image of Quadrilaterals ABCD and EFGH is not given but let us assume that they have the same orientation, hence:

∠A = ∠E = 47°

∠B = ∠F = 39°

∠C = ∠G = 112°

∠D = ∠H = 162°

3 0

3 years ago

Let f(x)=x^2+5x-36. Enter the x-intercepts of the quadratic function in the boxes.

Kipish [7]

Answer:

X Intercepts: (4,0) and -9,0

Step-by-step explanation:

8 0

3 years ago

PLEASE HELP

igomit [66]

Answer:

20 hours.

Step-by-step explanation.

The total distance traveled was 400 miles. Then I divided 400 by 20. I got 20.

5 0

3 years ago

A collar of Styrofoam is made to insulate a pipe. Find its volume. The large radius R is to the outer rim. The small radius r is

vesna_86 [32]

Answer:

the answer is 1 1/5

Step-by-step explanation:

8 0

3 years ago

What is the probability of rolling a four then a three

spayn [35]

Answer:

$\frac{1}{36}$

Step-by-step explanation:

Total possibilities when we a roll a die at a time are 6

given we should have four for first time and then three

let us assume we rolled the dice we may get 1,2,3,4,5,6(any of these) the probability to get 4 is

PROBABILITY= $\frac{\textrm{FAVOURABLE CHANCES}}{\textrm{TOTAL CHANCES}}$

Favourable chances=1

Total chances=6

Probability= $\frac{1}{6}$

the prabability to get 4 in first roll is $\frac{1}{6}$ .

let us assume we rolled the dice for second time again we may get 1,2,3,4,5,6(any of these) the probability to get 3 is

Favourable chances=1

total chances=6

probability= $\frac{1}{6}$

the probability to get 3 in second roll irrespective of first one is $\frac{1}{6}$

the probability to get 4 in first time and then 3 is

The probability to occur both events at a time is multiplication of individual probabilities

So,

probablility to get 4 in first roll= $\frac{1}{6}$

probability to get 3 in second roll= $\frac{1}{6}$

probability to occur both at a same time is = $\frac{1}{6}$ $\times$ $\frac{1}{6}$ = $\frac{1}{36}$

6 0

3 years ago