That's a huge number of points.
First: Calculate the value of 62 two pointers
62 * 2 = 124
Second: find the number of points that were due to 3 pointers.
151 - 124 = 27
Third: Divide by 3 to find the number of 3 pointers.
27÷3 = 9
Answer: There were 9 three pointers.
Answer:
10+c=3
Step-by-step explanation:
to solve this you would then subtract 10 from both sides, to get c by itself.
3-10= -7
Your answer would be -7 and the equation would be 10+c=3.
Answer: 53.13
Explanation of answer: since theta is the unknown, then you must use the inverse of sin. (Which is sin with -1 subscript) I used a calculator and used inverse of sin and put 4/5 in parenthesis
Answer:
Given:
Radius of large sphere: R1
Volume of sphere: V1
Radius of small sphere: R2
Volume of sphere: V2
R1=2R2
We know that:
Volume of a sphere: 4/3πR^3
Volume of large sphere: 4/3πR1^3
Now we know that R1=2R2(given)
Thus volume of large sphere(V1) 32/3πR2^3.
Volume of small sphere(V2): 4/3πR2^3.
Ratio of volume of large sphere to small sphere is 8:1.
Step-by-step explanation:
Answer:
There are a total of
functions.
Step-by-step explanation:
In order to define an injective monotone function from [3] to [6] we need to select 3 different values fromm {1,2,3,4,5,6} and assign the smallest one of them to 1, asign the intermediate value to 2 and the largest value to 3. That way the function is monotone and it satisfies what the problem asks.
The total way of selecting injective monotone functions is, therefore, the total amount of ways to pick 3 elements from a set of 6. That number is the combinatorial number of 6 with 3, in other words