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Elan Coil [88]
2 years ago
15

ADD 5y to the product of a and b.

Mathematics
2 answers:
In-s [12.5K]2 years ago
7 0
<h3><em>HELLO</em> ! </h3>

=  >  \: 5y \\ product \: of \: a \: and \: b \: is \: ab \:   \\ add \: this \: both \:  and \: u \: get \: the \: ans \: as \:  \\  =  >  \: 5y + ab \:

hope \: it \: helps \:  \\

vampyy \:

(ʘᴗʘ✿)

frozen [14]2 years ago
3 0

Answer:

5y+a-b

Step-by-step explanation:

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What value must x be for line y to be parallel to line z?
harkovskaia [24]
X=2 because (-8x+117)=101 if x=2 -8*2=-16. -16+117=101
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2 years ago
Need ASAP answer because I don’t not understand
dimaraw [331]

Hello there! The correct answer is B.

Note that in functions, x values cannot repeat. The points are given as (x, y) values, and you can see in the second option there are two -7s in the x values, making it not a function!

<em>I hope this was helpful, have a great rest of your day! If you need further help with this question, let me know!</em>

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3 years ago
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Which of the following is one of the cheapest routes to pass through each vertex once starting and ending with Vertex "A" and us
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3 years ago
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Mom has ⅘ quart of strawberries. She needs to fill ¼-quart jars. How many jars will she be able to fill?
Blababa [14]
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5 0
3 years ago
Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth.
likoan [24]

Answer:

Thus, the two root of the given quadratic equation x^2+4=6x is 5.24 and 0.76 .

Step-by-step explanation:

Consider, the given Quadratic equation, x^2+4=6x

This can be written as ,  x^2-6x+4=0

We have to solve using quadratic formula,

For a given quadratic equation ax^2+bx+c=0 we can find roots using,

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}  ...........(1)

Where,  \sqrt{b^2-4ac} is the discriminant.

Here, a = 1 , b = -6 , c = 4

Substitute in (1) , we get,

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

\Rightarrow x=\frac{-(-6)\pm\sqrt{(-6)^2-4\cdot 1 \cdot (4)}}{2 \cdot 1}

\Rightarrow x=\frac{6\pm\sqrt{20}}{2}

\Rightarrow x=\frac{6\pm 2\sqrt{5}}{2}

\Rightarrow x={3\pm \sqrt{5}}

\Rightarrow x_1={3+\sqrt{5}} and \Rightarrow x_2={3-\sqrt{5}}

We know \sqrt{5}=2.23607(approx)

Substitute, we get,

\Rightarrow x_1={3+2.23607}(approx) and \Rightarrow x_2={3-2.23607}(approx)

\Rightarrow x_1={5.23607}(approx) and \Rightarrow x_2=0.76393}(approx)

Thus, the two root of the given quadratic equation x^2+4=6x is 5.24 and 0.76 .

7 0
3 years ago
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