Answer:
The Zscore for both test is the same
Step-by-step explanation:
Given that :
TEST 1:
score (x) = 75
Mean (m) = 65
Standard deviation (s) = 8
TEST 2:
score (x) = 75
Mean (m) = 70
Standard deviation (s) = 4
USING the relation to obtain the standardized score :
Zscore = (x - m) / s
TEST 1:
Zscore = (75 - 65) / 8
Zscore = 10/8
Zscore = 1.25
TEST 2:
Zscore = (75 - 70) / 4
Zscore = 5/4
Zscore = 1.25
The standardized score for both test is the same.
Answer:
21.28 and 967.46
Hope it helps have a good night :)))))))))))))))))
Answer:

Step-by-step explanation:
To the find the equivalent of
, evaluate the expression. Start by opening the bracket.


Pair like terms


The equivalent of
is 
Answer:
b = 104
Step-by-step explanation:
Slope is expressed as;
m = y2-y1/x2-x1
14 = b - 6/5-(-2)
14 = b - 6/5+2
14 = b-6/7
Cross multiply
b-6 = 14 * 7
b - 6 = 98
b = 98 + 6
b = 104
Answer:
Using either method, we obtain: 
Step-by-step explanation:
a) By evaluating the integral:
![\frac{d}{dt} \int\limits^t_0 {\sqrt[8]{u^3} } \, du](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdt%7D%20%5Cint%5Climits%5Et_0%20%7B%5Csqrt%5B8%5D%7Bu%5E3%7D%20%7D%20%5C%2C%20du)
The integral itself can be evaluated by writing the root and exponent of the variable u as: ![\sqrt[8]{u^3} =u^{\frac{3}{8}](https://tex.z-dn.net/?f=%5Csqrt%5B8%5D%7Bu%5E3%7D%20%3Du%5E%7B%5Cfrac%7B3%7D%7B8%7D)
Then, an antiderivative of this is: 
which evaluated between the limits of integration gives:

and now the derivative of this expression with respect to "t" is:

b) by differentiating the integral directly: We use Part 1 of the Fundamental Theorem of Calculus which states:
"If f is continuous on [a,b] then

is continuous on [a,b], differentiable on (a,b) and 
Since this this function
is continuous starting at zero, and differentiable on values larger than zero, then we can apply the theorem. That means:
