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Tju [1.3M]
3 years ago
12

The Math Counts Club had a party at their school. There were 20 cookies and 40 slices of pizza to be shared equally. Each studen

t had the same number of whole cookies and the same number of slices of pizza with nothing left over. How many students could have been at the party? LCM or GCF?
Mathematics
1 answer:
pychu [463]3 years ago
4 0

Answer:

  • 2, 4, 10 or 20 students

Step-by-step explanation:

<u>Prime factors:</u>

  • 20 = 2*2*5
  • 40 = 2*2*2*5

<u>Common factors of the two numbers: </u>

  • 2, 4, 10, 20

Possible number of students as above

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Compare the scores: a score of 75 on a test with a mean of 65 and a standard deviation of 8 and a score of 75 on a test with a m
LiRa [457]

Answer:

The Zscore for both test is the same

Step-by-step explanation:

Given that :

TEST 1:

score (x) = 75

Mean (m) = 65

Standard deviation (s) = 8

TEST 2:

score (x) = 75

Mean (m) = 70

Standard deviation (s) = 4

USING the relation to obtain the standardized score :

Zscore = (x - m) / s

TEST 1:

Zscore = (75 - 65) / 8

Zscore = 10/8

Zscore = 1.25

TEST 2:

Zscore = (75 - 70) / 4

Zscore = 5/4

Zscore = 1.25

The standardized score for both test is the same.

7 0
2 years ago
Round each to the nearest cent.<br> $21.277<br> $967.46
Nat2105 [25]

Answer:

21.28 and 967.46

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3 0
3 years ago
Select the answer choice that is equivalent to the expression given belon.
uranmaximum [27]

Answer:

23x - 10

Step-by-step explanation:

To the find the equivalent of 9(2x - 3) + 5x + 17, evaluate the expression. Start by opening the bracket.

9*2x - 9*3 + 5x + 17

18x - 27 + 5x + 17

Pair like terms

18x + 5x - 27 + 17

23x - 10

The equivalent of 9(2x - 3) + 5x + 17 is 23x - 10

6 0
3 years ago
If the gradient of a line joining the points (-2, 6) and (5, b) is 14.<br> Find the value of b.
babunello [35]

Answer:

b = 104

Step-by-step explanation:

Slope is expressed as;

m = y2-y1/x2-x1

14 = b - 6/5-(-2)

14 = b - 6/5+2

14 = b-6/7

Cross multiply

b-6 = 14 * 7

b - 6 = 98

b  = 98 + 6

b = 104

3 0
3 years ago
Find the derivative.
Aleksandr [31]

Answer:

Using either method, we obtain:  t^\frac{3}{8}

Step-by-step explanation:

a) By evaluating the integral:

 \frac{d}{dt} \int\limits^t_0 {\sqrt[8]{u^3} } \, du

The integral itself can be evaluated by writing the root and exponent of the variable u as:   \sqrt[8]{u^3} =u^{\frac{3}{8}

Then, an antiderivative of this is: \frac{8}{11} u^\frac{3+8}{8} =\frac{8}{11} u^\frac{11}{8}

which evaluated between the limits of integration gives:

\frac{8}{11} t^\frac{11}{8}-\frac{8}{11} 0^\frac{11}{8}=\frac{8}{11} t^\frac{11}{8}

and now the derivative of this expression with respect to "t" is:

\frac{d}{dt} (\frac{8}{11} t^\frac{11}{8})=\frac{8}{11}\,*\,\frac{11}{8}\,t^\frac{3}{8}=t^\frac{3}{8}

b) by differentiating the integral directly: We use Part 1 of the Fundamental Theorem of Calculus which states:

"If f is continuous on [a,b] then

g(x)=\int\limits^x_a {f(t)} \, dt

is continuous on [a,b], differentiable on (a,b) and  g'(x)=f(x)

Since this this function u^{\frac{3}{8} is continuous starting at zero, and differentiable on values larger than zero, then we can apply the theorem. That means:

\frac{d}{dt} \int\limits^t_0 {u^\frac{3}{8} } } \, du=t^\frac{3}{8}

5 0
3 years ago
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