The coordinates for a quadrilateral are (-8, -3), (-7,7), (3, 6) and (2, -4). Determine the type of quadrilateral.

What is the distance between the following points?

GaryK [48]

Point are

(2,-3)
(8,-9)

Using distance formula

$\\ \sf\longmapsto \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$\\ \sf\longmapsto \sqrt{(8-2)^2+(-9+3)^2}$

$\\ \sf\longmapsto \sqrt{6^2+(-6)^2}$

$\\ \sf\longmapsto \sqrt{36+36}$

$\\ \sf\longmapsto \sqrt{72}$

$\\ \sf\longmapsto 8.2units$

4 0

3 years ago

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The figure is made up of a cylinder and a hemisphere. To the nearest whole number, what is the approximate volume of this figure

Novosadov [1.4K]

Hello!

The figure is made up of a cylinder and a hemisphere. To the nearest whole number, what is the approximate volume of this figure?

Use 3.14 to approximate π .

Enter your answer in the box. in.³

Data: (Cylinder)

h (height) = 7 in

r (radius) = 2.5 in (The diameter is 5 being twice the radius)

Adopting: $\pi \approx 3.14$

V (volume) = ?

Solving: (Cylinder volume)

$V = \pi *r^2*h$

$V = 3.14 *2.5^2*7$

$V = 3.14*6.25*7$

$V = 137.375 \to \boxed{V_{cylinder} \approx 137.38\:in^3}$

Note: Now, let's find the volume of a hemisphere.

Data: (hemisphere volume)

V (volume) = ?

r (radius) = 2.5 in (The diameter is 5 being twice the radius)

Adopting: $\pi \approx 3.14$

If: We know that the volume of a sphere is $V = 4* \pi * \dfrac{r^3}{3}$ , but we have a hemisphere, so the formula will be half the volume of the hemisphere $V = \dfrac{1}{2}* 4* \pi * \dfrac{r^3}{3} \to \boxed{V = 2* \pi * \dfrac{r^3}{3}}$

Formula: (Volume of the hemisphere)

$V = 2* \pi * \dfrac{r^3}{3}$

Solving:

$V = 2* \pi * \dfrac{r^3}{3}$

$V = 2*3.14 * \dfrac{2.5^3}{3}$

$V = 2*3.14 * \dfrac{15.625}{3}$

$V = \dfrac{98.125}{3}$

$\boxed{ V_{hemisphere} \approx 32.70\:in^3}$

Now, to find the total volume of the figure, add the values: (cylinder volume + hemisphere volume)

Volume of the figure = cylinder volume + hemisphere volume

Volume of the figure = 137.38 in³ + 32.70 in³

$Volume\:of\:the\:figure =170.08 \to \boxed{\boxed{\boxed{Volume\:of\:the\:figure = 170\:in^3}}}\end{array}}\qquad\quad\checkmark$

_______________________

I Hope this helps, greetings ... Dexteright02! =)

5 0

3 years ago

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Can someone please help me with this please I really need help

Lubov Fominskaja [6]

Answer:N

Step-by-step explanation:

6 0

3 years ago

Helppppp asaaaap pleaseeee number 6 only

kari74 [83]

The remandor of the first number is the answer

5 0

3 years ago

ron’s class donated d dollars to a local charity. Danny’s class donated 21% more than Ron’s class. Which expression shows the am

Arte-miy333 [17]

You can clearly eliminate 0.79d as an answer, because that is less than the amount that Ron's class donated. The last answer is also incorrect, because it states that Danny's class donated 21 more cents than Ron's class. The problem says that Danny's class donated 21% more than Ron's. The only way that d + 0.21 would be correct is if Ron's class donated $1. The problem does not say that. Therefore, we are left with two possibilities. The first choice is the correct one. Why?

21% more than Ron's class' donation would be the amount that Ron's class donated + an additional 21%. If Ron's class donated d dollars, then an additional 21% would be 0.21 * d = 0.21d. Hence, Danny's class donated a total of:

d + 0.21d = d(1 + 0.21) = 1.21d

6 0

3 years ago