Question

In a Gallup poll of randomly selected adults, 66% said that they worry about identity theft. For a group of 1013 adults, the mean of those who do not worry about identify theft is closest to:

Answer 1

Answer:

$Mean = 344$

Step-by-step explanation:

Given

$Population = 1013$

Let p represents the proportion of those who worry about identity theft;

$p = 66\%$

Required

Mean of those who do not worry about identity theft

First, the proportion of those who do not worry, has to be calculated;

Represent this with q

In probability;

$p + q = 1$

Make q the subject of formula

$q = 1 - p$

Substitute $p = 66\%$

$q = 1 - 66\%$

Convert percentage to fraction

$q = 1 - 0.66$

$q = 0.34$

Now, the mean can be calculated using:

$Mean = nq$

Where n represents the population

$Mean = 1013 * 0.34$

$Mean = 344.42$

$Mean = 344$ (Approximated)