Please Answer ASAP

Mathematics

2 answers:

Masteriza [31]3 years ago

6 0

hence, the common ratio of the given G.P. is 3 or −3.

kotykmax [81]3 years ago

6 0

Answer:

common ratio is -3 or 3

Step-by-step explanation:

$u_1=1\\\\u_3=u_1*r^2=r^2\\\\u_5=u_1*r^4=r^4\\\\r^2+r^4=90\\\\r^4+r^2-90=0\\\Delta=1+4*90=361=19^2\\\\r^2=\dfrac{-1-19}{2} =-10 (exclude\ a\ square\ is\ positive)\\or\\r^2=\dfrac{-1+19}{2}=9\\r^2-9=0\\(r-3)(r+3)=0\\So\ r=-3\ or\ r=3\\$

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PLEASE HELP!!!! WILL MARK BRAINLIEST!!!!

irga5000 [103]

Answer:

None of these.

Step-by-step explanation:

Let's assume we are trying to figure out if (x-6) is a factor. We got the quotient (x^2+6) and the remainder 13 according to the problem. So we know (x-6) is not a factor because the remainder wasn't zero.

Let's assume we are trying to figure out if (x^2+6) is a factor. The quotient is (x-6) and the remainder is 13 according to the problem. So we know (x^2+6) is not a factor because the remainder wasn't zero.

In order for 13 to be a factor of P, all the terms of P must be divisible by 13. That just means you can reduce it to a form that is not a fraction.

If we look at the first term x^3 and we divide it by 13 we get $\frac{x^3}{13}$ we cannot reduce it so it is not a fraction so 13 is not a factor of P