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3 years ago

Please Answer ASAP

Mathematics

2 answers:

Masteriza [31]3 years ago

6 0

hence, the common ratio of the given G.P. is 3 or −3.

kotykmax [81]3 years ago

6 0

Answer:

common ratio is -3 or 3

Step-by-step explanation:

$u_1=1\\\\u_3=u_1*r^2=r^2\\\\u_5=u_1*r^4=r^4\\\\r^2+r^4=90\\\\r^4+r^2-90=0\\\Delta=1+4*90=361=19^2\\\\r^2=\dfrac{-1-19}{2} =-10 (exclude\ a\ square\ is\ positive)\\or\\r^2=\dfrac{-1+19}{2}=9\\r^2-9=0\\(r-3)(r+3)=0\\So\ r=-3\ or\ r=3\\$

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The length of the rectangle is x cm. The length of a diagonal of the rectangle is 8 crn. The perimeter of the rectangle is 20 cm

klemol [59]

Answer:

$x^2-10x+18=0$

a = -10 and b = 18.

Step-by-step explanation:

Let w represent the width of the rectangle.

We are given that the perimeter of the rectangle is 20 cm, this means that:

$20=2(x + w)$

Let's put w in terms of x. Divide both sides by two:

$10=x+w$

And solve for w:

$w=10-x$

So, the rectangle measures x by (10 - x) cm.

According to the Pythagorean Theorem:

$a^2+b^2=c^2$

a and b are the legs and c is the hypotenuse.

Substitute x for a, w for b, and 8 for c:

$x^2+w^2=8^2$

Simplify and substitute:

$x^2+(10-x)^2=64$

Square:

$x^2+(100-20x+x^2)=64$

Isolate the equation. So:

$2x^2-20x+36=0$

Since the leading coefficient is one, divide both sides by two:

$x^2-10x+18=0$

Therefore, a = -10 and b = 18.

6 0

2 years ago

If f(x) = x3, what is the equation of the graphed function?

jolli1 [7]

I think the answer is A. But I’m not fully sure

5 0

2 years ago

Y=x-5; domain = {4,6,8}

Lostsunrise [7]

Answer:

Range = {-1, 1, 3}

Step-by-step explanation:

The question asks for the range.

The function given is

$y=x-5$

The domain is the set of 3 numbers:

Domain = {4,6,8}

We need to find the range.

First, the range is the set of all y-values for which the function is defined.

When we will be given the domain with a set of numbers, the range would be the numbers that we get when we evaluate the the function at those numbers.

So, we evaluate the function (y-values) at x = 4,6, and 8.

At x = 4:

$y=x-5\\y=4-5\\y=-1$