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DiKsa [7]
3 years ago
7

5 1/2 is how many half cups?

Mathematics
1 answer:
QveST [7]3 years ago
3 0
11 cups is how many 5 and a half cups is in half cups
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A drone costs $300 plus $25 for each set of extra propellers write a independent variable​
velikii [3]

Answer:

Drone = $300

4 Extra Set Of Propellor = 4(25$) = $100

Step-by-step explanation:

7 0
3 years ago
Larry bought 4 lemonades for his friends.Each lemonades cost $1.28.Complete the table to show the prices of 2,3,and 4 lemonades
pogonyaev
2 drinks-$2.56
3 drinks-$3.84
4 drinks-$5.12
hope that this helps
4 0
3 years ago
Read 2 more answers
Please please help me!!!
shutvik [7]

Answer:

D

Step-by-step explanation:

Suppose she only fills her big pots. The number of big pots filled is 120÷12=10. So the y-intercept is (0,10).

Now suppose she only fills her small pots. The number of small pots filled is 120÷5=24. So the x-intercept is (24,0)

6 0
3 years ago
Shenny earned $25 after babysitting for 3 hours ​
tangare [24]

Answer:

i dont know 75 dollars

Step-by-step explanation:

5 0
3 years ago
The average undergraduate cost for tuition, fees, and room and board for two-year institutions last year was $13,252. The follow
kipiarov [429]

Answer:

The p-value of the test is 0.0041 < 0.05, which means that there is sufficient evidence at the 0.05 significance level to conclude that the mean cost has increased.

Step-by-step explanation:

The average undergraduate cost for tuition, fees, and room and board for two-year institutions last year was $13,252. Test if the mean cost has increased.

At the null hypothesis, we test if the mean cost is still the same, that is:

H_0: \mu = 13252

At the alternative hypothesis, we test if the mean cost has increased, that is:

H_1: \mu > 13252

The test statistic is:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, s is the standard deviation and n is the size of the sample.

13252 is tested at the null hypothesis:

This means that \mu = 13252

The following year, a random sample of 20 two-year institutions had a mean of $15,560 and a standard deviation of $3500.

This means that n = 20, X = 15560, s = 3500

Value of the test statistic:

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{15560 - 13252}{\frac{3500}{\sqrt{20}}}

t = 2.95

P-value of the test and decision:

The p-value of the test is found using a t-score calculator, with a right-tailed test, with 20-1 = 19 degrees of freedom and t = 2.95. Thus, the p-value of the test is 0.0041.

The p-value of the test is 0.0041 < 0.05, which means that there is sufficient evidence at the 0.05 significance level to conclude that the mean cost has increased.

7 0
3 years ago
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