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DENIUS [597]
3 years ago
8

Raul uses a credit card to take out a 3-year loan of $4500 at a rate of 15% to purchase

Mathematics
1 answer:
mars1129 [50]3 years ago
7 0

Answer:

Amount of loan pay = $6.840 (Approx.)

Step-by-step explanation:

Given:

Amount of loan borrow = $4,500

Rate of interest = 15% = 0.15

Number of year = 3 year

Find:

Amount of loan pay

Computation:

Future value = Present value[1+r]ⁿ

Amount of loan pay = Amount of loan borrow[1+r]ⁿ

Amount of loan pay = 4,500[1+0.15]³

Amount of loan pay = 4,500[1.15]³

Amount of loan pay = 4,500[1.52]

Amount of loan pay = $6.840 (Approx.)

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Please asap!!!!! (photo below)
Bond [772]

Answer:

132 degrees

Step-by-step explanation:

these angles are Alternate interior angles so angle A is congruent to angle B.

5x-18 = 3x+42

-3x         -3x

2x-18 = 42

+18       +18

2x    =   60

÷2     ÷2

x=30

A=5(30) -18

  = 150-18

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HOPE THIS HELPS

6 0
4 years ago
Please help ill mark brainliest​
lesantik [10]

Answer:

I think its A ratio reduced, since a scale factor is the ratio of the length of a side of one figure to the length of the corresponding side of the other figure.

7 0
3 years ago
Read 2 more answers
Newton's Method: Calculus I need assistance and a clear explanation so I can understand. Please be clear
marishachu [46]
Newtons method is a way to approximate the zero of a function. 
It is a recursive method such that the output becomes the new input, the goal is to approach the zero by having the inputs change by a smaller amount each iteration until that change is nearly 0.

First, let me explain where the method comes from.
The formula is really just a manipulation of the slope formula using 2 points; the point tangent to the curve, and the point where the tangent line crosses the x-axis.
If (x,y) is point on curve, then (x*,0) is point on tangent line at x-axis.
m = \frac{dy}{dx} = \frac{y - 0}{x - x^*}

Rearranging for x*:
x^* = x - \frac{y}{dy/dx}

This is the formula for newtons method. y = f(x), dy/dx = f'(x)
Now what happens is (x*,y*) becomes new point on curve with new tangent line with different slope.
This new line will cross x-axis at different point x** and so on until eventually f(x) gets really really close to 0.

Now for the example:
you need to take derivative f'(x) using product rule:
f(x) = x tan(x) - 1 \\  \\ f'(x) = tan(x) + x sec^2 (x)

Then its just a matter of plugging in values for x, and repeating until we get close to a zero.

First plug in x = 1
x_1 = 1 - \frac{(1)(tan 1) - 1}{tan 1 + (1)sec^2 (1)} = 0.888136 \\  \\ x_2 = .888136 - \frac{f(.888136)}{f'(.888136)} = 0.861465 \\  \\ x_3 = .861465 - \frac{f(.861465)}{f'(.861465)} = 0.860335 \\  \\ x_4 = .860335 - \frac{f(.860335)}{f'(.860335)} = 0.860334 \\  \\ x_5 = .860334 - \frac{f(.860334)}{f'(.860334)} = 0.860334

Now we can stop because x5 = x4 to 6 decimals, this means f(x) is very close to 0 and will serve as a good approximation for a solution.

Final Answer:
x = 0.860334
8 0
3 years ago
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Pepsi [2]
Notice, is a vertical line, when x = 2, y = 3, when x = 1,000,000,000 y = 3 when x = whatever, y = 3

thus, check the picture below

6 0
3 years ago
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Ahat [919]

Answer:

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Step-by-step explanation:

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3 years ago
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