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Tems11 [23]
2 years ago
13

What is the value of the angle marked m? P​

Mathematics
1 answer:
Anettt [7]2 years ago
3 0

Answer:

180

Step-by-step explanation:

bcoz it's a straight angle

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The diameter of a sphere is 6 ft. Find the exact volume of the sphere.
OleMash [197]

Answer:

V ≈ 113.1ft³

Step-by-step explanation:

the answer is V ≈ 113.1ft³.

I hope this helps you.

6 0
3 years ago
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Add x^3 - 4x^2 + 1 to 3x^2 + x <br> Show Your work!
Sladkaya [172]

\qquad \qquad\huge \underline{\boxed{\sf Answer}}

Let's solve ~

\qquad \sf  \dashrightarrow \: (x {}^{3}  - 4x {}^{2}  + 1) + (3 {x}^{2}  + x)

\qquad \sf  \dashrightarrow \:  {x}^{3}  - 4 {x}^{2}  + 1 + 3 {x}^{2}  + x

\qquad \sf  \dashrightarrow \:  {x}^{3}  - 4 {x}^{2}  + 3x {}^{2}  + x + 1

\qquad \sf  \dashrightarrow \:  {x}^{3}  -  {x}^{2}  + x + 1

6 0
2 years ago
Differentiate Functions of Other Bases In Exercise, find the derivative of the function.
WARRIOR [948]

Answer:

\dfrac{dy}{dx} =\dfrac{2 x + 6}{ \log{\left (10 \right )}\left(x^{2} + 6 x\right)}

Step-by-step explanation:

given

y = \log_{10}{(x^2+6x)}

using the property of log \log_ab=\frac{log_cb}{log_ca}, and if c =e,\log_ab=\frac{ln{b}}{ln{a}}, we can rewrite our function as:

y = \dfrac{\ln{\left (x^{2} + 6 x \right )}}{\ln{\left (10 \right )}}

now we can easily differentiate:

\dfrac{dy}{dx} = \dfrac{1}{\ln{10}}\left(\dfrac{d}{dx}(\ln{(x^{2} + 6x)})\right)

\dfrac{dy}{dx} = \dfrac{1}{\ln{10}}\left(\dfrac{2x+6}{x^{2} + 6x}\right)

\dfrac{dy}{dx} =\dfrac{2 x + 6}{ \log{\left (10 \right )}\left(x^{2} + 6 x\right)}

This is our answer!

3 0
3 years ago
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Really need help with this pls help!!
worty [1.4K]

Let's carry this math sentence over to its natural, "shapey" element. We're going to look at each term not as an ordinary number, but as <em>the area of some shape</em>.

x² (read as "x <em>squared"</em>) can be seen as the area of a square with side lengths of x. 2x can similarly be seen as the area of a <em>rectangle </em>with a length of x and a width of 2. (Picture 1)

What's our question actually asking, though? Something about <em>perfect squares</em>. More specifically, we're looking for something to add on that'll <em>make this thing a perfect square</em>. We're trying to find a missing piece we can slot in to make a square, in other words. Problem is, our shapes don't look much like a square if we put them together right now. We need to do a little cutting and gluing first.

First, we're gonna cut the 2x rectangle lengthwise, getting two rectangles with an area of x, a length of 1, and a width of x. Next, we're going to attach them to the x² square, creating this shape that looks, strangely, like a square with a little bit missing from it (picture 2). What we're trying to do is <em>complete this square, </em>to find the area of that little missing chunk.

As it turns out, we have all the information we need for this. Notice that, using the lengths of the x rectangles, we can find that the square's dimensions are 1 x 1, which means that its area is 1 x 1  = 1.

If we tack this new area on to our original expression, we've "completed the square!" We now have a perfect square with side lengths of (x + 1) and an area of (x + 1)² (picture 3).

So, our final expression is x² + 2x + 1, and the missing constant - the area of the "missing square" we had to find to complete our larger one - is 1.

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3 years ago
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