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Sonja [21]
2 years ago
9

Each face of a cube is a square with a side length of 3 meters. What is the total area of all the faces of the cube?

Mathematics
2 answers:
Stells [14]2 years ago
3 0

Answer:

I am pretty sure it is 9

Step-by-step explanation:

Since a cube has the same with and length on every side is the same so I just do 3x3=9

dezoksy [38]2 years ago
3 0

Answer: 54

Step-by-step explanation:

A cube is a perfect square to find the area use L x W and if the length is 3, the width is 9

A cube has 6 sides, so 9 x 6 = 54

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A Park has a pond shaped like a quadrilateral with all sides 18 feet long and at least one right angle. What geometric shape bes
Rom4ik [11]
I gave some examples of some quadrilaterals. The pond is most likely the shape of a square or a triangle with a right angle.

5 0
3 years ago
Two trains are 210 miles apart, and their speeds differ by 17 mph. Find the speed of each train if they are traveling toward eac
Marizza181 [45]
V1 - velocity first train
v2 - velocity second train
v2 > v1

v2 - v1 = 17 mph

We know, that: 
s_1+s_2=210 \ [miles] \\ \\ t_1=t_2=2h

So:

v_1=\dfrac{s_1}{t_1}=\dfrac{s_1}{2} \\ \\ v_2=\dfrac{s_2}{t_2}=\dfrac{s_2}{2} \\ \\ \\ v_1+v_2= \dfrac{s_1}{2}+\dfrac{s_2}{2} \\ \\ v_1+v_2= \dfrac{s_1+s_2}{2} \\ \\  v_1+v_2= \dfrac{210}{2}=105

NOw we've got simple system of equations:

+\begin{cases} v_2-v_1=17 \\ v_2+v_1=105\end{cases} \\ \\ 2v_2=122 \qquad /:2 \\ \\ v_2=61 \qquad [mph] \\ \\ v_2-v_1=17 \\ \\ 61-v_1=17 \\ \\ v_1=44

Velocities of these trains are  61mph  and 44mph

3 0
3 years ago
Read 2 more answers
Afish is swimming 102 feet below the surface of the water i fer descents another 125 What subtraction expression can be used to
s344n2d4d5 [400]
You would simply do -102-125 to give -227 feet below the surface
7 0
3 years ago
Pls help photo included !!!!
AlladinOne [14]

1. 371.25

2. 742.5

3.185.625

6 0
3 years ago
Y= x^2 -5 solve for x
dexar [7]

Y= x^2 -5

We need to solve for x, we need to get x alone

Y= x^2 -5

Lets start by removing -5

Add 5 on both sides

y + 5= x^2 -5 + 5

y + 5= x^2

Now to isolate x , we need to remove the square from x

To remove square , take square root on both sides

+-\sqrt{y+5} = \sqrt{x^2}

square and square root will get cancelled

+-\sqrt{y+5} = x

So x = +\sqrt{y+5} and  x = -\sqrt{y+5}


7 0
3 years ago
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