Answer:
Step-by-step explanation:The Monarch Butterfly Biosphere Reserve is a World Heritage Site containing most of the ... The monarch butterflies migration patterns are altered by climate change. During migration ... This area is predominantly covered in forests. ... These colonies are dense, with between six and sixty million butterflies per hectare.
Given :
The diagonals of rhombus ABCD intersect at E.
∠CAD = 20°.
To Find :
The angle ∠CDA.
Solution :
We know, diagonals of a rhombus bisects each other perpendicularly.
So, ∠DEA = 90°.
In triangle ΔEAD :
∠EAD + ∠AED + ∠EDA = 180°
20° + 90° + ∠EDA = 180°
∠EDA = 70°
Now, we know diagonal of rhombus also bisect the angle between two sides .
So, ∠CDA = 2∠EDA
∠CDA = 2×70°
∠CDA =140°
Therefore, ∠CDA is 140°.
3. 3X3X3=27............................
3x+(x-2)=10
4x=12
x=12/4=3
y=x-2=3-2=1
so, x=3 and y=1
Answer: (3;1)
Answer:
- arc second of longitude: 75.322 ft
- arc second of latitude: 101.355 ft
Explanation:
The circumference of the earth at the given radius is ...
2π(20,906,000 ft) ≈ 131,356,272 ft
If that circumference represents 360°, as it does for latitude, then we can find the length of an arc-second by dividing by the number of arc-seconds in 360°. That number is ...
(360°/circle)×(60 min/°)×(60 sec/min) = 1,296,000 sec/circle
Then one arc-second is
(131,356,272 ft/circle)/(1,296,000 sec/circle) = 101.355 ft/arc-second
__
Each degree of latitude has the same spacing as every other degree of latitude everywhere. So, this distance is the length of one arc-second of latitude: 101.355 ft.
_____
<em>Comment on these distance measures</em>
We consider the Earth to have a spherical shape for this problem. It is worth noting that the measure of one degree of latitude is almost exactly 1 nautical mile--an easy relationship to remember.
