Answer:
Draw a graph of f(x) and q(x) also find x-intercept and y
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Answer:
y = 3x^2 +30x +69
Step-by-step explanation:
Transformations work this way:
g(x) = k·f(x) . . . . vertical stretch by a factor of k
g(x) = f(x -h) +k . . . . translation (right, up) by (h, k)
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So, the translation down 2 units will make the function be ...
f(x) = x^2 ⇒ f1(x) = f(x) -2 = x^2 -2
The vertical stretch by a factor of 3 will make the function be ...
f1(x) = x^2 -2 ⇒ 3·f1(x) = f2(x) = 3(x^2 -2)
The horizontal translation left 5 units will make the function be ...
f2(x) = 3(x^2 -2) ⇒ f2(x +5) = f3(x) = 3((x +5)^2 -2)
The transformed function equation can be written ...
y = 3((x +5)^2 -2) = 3(x^2 +10x +25 -2)
y = 3x^2 +30x +69
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The attachment shows the original function and the various transformations. Note that the final function is translated down 6 units from the original. That is because the down translation came <em>before</em> the vertical scaling.
Answer: OPTION C
Step-by-step explanation:
You can solve the problem shown above keeping on mind the facts shown below:
As you can see in the graph attached in the problem, there is a hole in the function at x=6.
By definition, this indicates that the function shown is not continuous at that point.
Therefore, you can conclude that the value in which is the graph discontinuous is the value of the option c: 6
Yes that is the answer 19