Question

A horse owner has 50 lbs of hay that is 6% protein by weight. He adds x lbs of oats that is 12% protein by weight.

Answer 1

Answer:

y-intercept = 0.06 = 6%

Step-by-step explanation:

As per the statement:

A horse owner has 50 lbs of hay that is 6% protein by weight. He adds x lbs of oats that is 12% protein by weight.

Given the function:

$y = \frac{0.06(50)+0.12x}{50+x}$

where, y represents the percent of protein in the final mixture of feed.

We have to find  y-intercept of the function that models the percent of protein in the final mixture.

Y-intercept:

Substitute x = 0 and solve for y:

then;

$y = \frac{0.06(50)+0.12(0)}{50+0}=\frac{0.60 \cdot 50}{50}$

⇒$y = 0.06 =6\%$

Therefore, the y-intercept of the function that models the percent of protein in the final mixture is, 6%

Answer 2

The second part of the problem is "The amount of protein the feed has if no oats are added."