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NeX [460]
2 years ago
7

7. Find the missing lengths of the sides

Mathematics
1 answer:
Aleonysh [2.5K]2 years ago
7 0

Answer:

a = b = 12 feet.

Step-by-step explanation:

An isosceles right triangle always has its sides in the ratio 1:1:√2.

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Solve for x. 47x=2747x=27
Svetach [21]
Divide by the coefficient of x.
  x = 27/47
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3 years ago
What is the correct solution to this problem? A number divided by 5 is 3 more than –6. What is the number? A. –45 B. –30 C. –15
mihalych1998 [28]
<span>A number divided by 5 is 3 more than –6.
Let the number be "x".

x/5 = -6 + 3
First combine like terms.
x/5 = -3
Now multiply both sides by 5 to get x on one side.
x = -15

The answer is
C. -15
</span>
4 0
3 years ago
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Need answers for a b and c, please help
rewona [7]
B is F and C is to the right 2 and down 3
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3 years ago
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How many pounds of candy that cells for $0.66 per Ib must be mixed with candy that sells for $1.31 per Ib to obtain 9 Ib of a mi
faltersainse [42]

Answer:  \frac{306}{65} pounds

Step-by-step explanation:

Let x pounds of $ 0.66 per lb candies mixed with y pounds of $ 1.31 per lb candies to obtain 9 lb of $ 0.97 per lb candies,

Hence, we can write,

x + y = 9 ------- (1)

And, 0.66 of x + 1.31 of y = 0.97 of (x + y)

⇒ 66 x + 131 y = 97 (x+y)

⇒ 66 x +131 y - 97 x - 97 y = 0

⇒ -31 x + 34 y = 0  ------(2)

By solving equation (1) and (2)

We get,

x=\frac{306}{65} and y=\frac{279}{65}

Hence, the quantity of 0.66 per lb candies = \frac{306}{65}  pounds

7 0
2 years ago
A circle with radius 3 has a sector with a central angle of 1/9 pi radians
Art [367]

The area of sector is 1.57 m²

<u>Explanation:</u>

Given:

Radius, r = 3 m

Central angle of a sector = 1/9π radians

Area of sector, A = ?

We know:

Area of sector, A = \frac{1}{2} r^2 \alpha

where,

α is the central angle in radians

On substituting the value we get:

A = \frac{1}{2} X(3)^2 X \frac{1}{9}X 3.14\\ \\A = 1.57 m^2

Therefore, the area of sector is 1.57 m²

5 0
3 years ago
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