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4 years ago

The graph below shows the transformation from triangle 1 to triangle 2.

Mathematics

2 answers:

zmey [24]4 years ago

6 0

Answer:

reflect across the y-axis; rotate 180° counterclockwise about the origin - first choice

mestny [16]4 years ago

3 0

Answer:

Option A.

Step-by-step explanation:

The graph below shows the transformation from triangle 1 to triangle 2 as below.

1). To understand the transformation we will take a point A. Present coordinates of point A are (1, -1).

When point A is reflected across y - axis, coordinates of A' become (1, 1).

2). Now we see that triangle 2 is in 3rd quadrant having coordinates A"(-1, -1)

which reveals that A'(1, 1) has been rotated by 180° counterclockwise.

Therefore, option A. is the correct choice.

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Find the possible values of x. the perimeter is less than or equal to 51 meters.

sertanlavr [38]

Answer-

The value of x can be anything between 0 to 15

Solution-

Perimeter of a geometrical figure is the sum of lengths of all its sides.

So, the value of the perimeter of the given pentagon would be,

$=8+8+10+10+x\\\\=(36+x)\ meters$

As given in the question that, the perimeter is less than or equal to 51 meters.

So,

$\Rightarrow 36+x\leq 51$

$\Rightarrow x\leq 15$

As the side length can not be negative, so x must be positive, i.e

$0$

5 0

3 years ago

A shop advertised "Everything half price

Aleks04 [339]

Your answer would be 57.5%.

7 0

3 years ago

There are 12 grams of sugar in 1/3 of a piece of candy. How much sugar is in 3/4

Mariana [72]

Hi! This problem be set up with a ratio or fraction. 12/.333 = x/.75
Cross multiply
9=.333x
divide by .333 on each side
giving you x=27
There are 27 grams of sugar in a 3/4 piece of candy

7 0

3 years ago

Medians $\overline{dp}$ and $\overline{eq}$ of $\triangle def$ are perpendicular. if $dp= 18$ and $eq = 24$, then what is ${de}$

monitta

Denote by M the point of intersection of the medians.
Denote also the distance DM by x and the distance QM by y.
From the median properties of triangles we know that
$y=\frac{1}{3}\timesFQ=\frac{1}{3}\times24=8$
Also,
$x=\frac{2}{3}\times DP=\frac{2}{3}\times 18=12$
Since the medians are perpendicular, we deduce that:
$x^2+y^2=DQ^2\iff DQ=\sqrt{8^2+12^2}=14.4$
Then, since $DE=2\times DQ\text{ then }DE=2\times 14.4=28.8$