Question

50 POINTS!!! GIVE A LEGITIMATE ANSWER!!!

Answer 1

${x}^{2} + 4x + {y}^{2} - 6y = - 4$

Add both sides of the equation plus 4

${x}^{2} + 4x + 4 + {y}^{2} - 6y = - 4 + 4$

Add both sides of the equation plus 9

${x}^{2} + 4x + 4 + {y}^{2} - 6y + 9 = 0 + 9$

$({x + 2})^{2} + ( {y - 3})^{2} = 9$

Thus the center and the radius of the circle would be :

$center = o = ( - 2 \: \: , \: \: 3 \: )$

$radius \: = r$

${r}^{2} = 9$

Thus ;

$r = 3$

And we're done .....