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3 years ago

Hello, happy Friday, I am just here with some geometry questions.

Mathematics

1 answer:

Virty [35]3 years ago

5 0

Answer:

Given triangle:

ΔXYZ
X(-1,2), Y(2,1), Z(-1, -2)

D₀.₅(ΔXYZ) results in:

(x, y) → (0.5x, 0.5y)
X'(-0.5, 1), Y'(1, 0.5), Z(-0.5, -1)

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Simplify this expression 5.3x-2.2(9.6x-9.11)

USPshnik [31]

−15.82x + 20.042
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3 years ago

The fraction of defective integrated circuits produced in a photolithography process is being studied. A random sample of 300 ci

Olenka [21]

Answer:

The correct answer is

(0.0128, 0.0532)

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence interval $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

Z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$

For this problem, we have that:

In a random sample of 300 circuits, 10 are defective. This means that $n = 300$ and $\pi = \frac{10}{300} = 0.033$

Calculate a 95% two-sided confidence interval on the fraction of defective circuits produced by this particular tool.

So $\alpha$ = 0.05, z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{300}} = 0.033 - 1.96\sqrt{\frac{0.033*0.967}{300}} = 0.0128$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{300}} = 0.033 + 1.96\sqrt{\frac{0.033*0.967}{300}} = 0.0532$

The correct answer is

(0.0128, 0.0532)

4 0

3 years ago

(01.05 LC) Simplify (95)7

ankoles [38]

Are you doing online school? I am and i need this as well :(

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3 years ago

PLEASE HELP! Thank you if you helped! Will give Brainliest

pogonyaev

Rent all

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74/4 = 18.5

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A-1

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3 years ago

Ella went trick-or-treating with her family. When

Kazeer [188]

Answer:

Step-by-step explanation:

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2 years ago

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