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creativ13 [48]
2 years ago
10

Use the empirical rule to find a reasonable estimate for P(z ≤ 0. 82). 10% 30% 50% 80%.

Mathematics
1 answer:
o-na [289]2 years ago
3 0

P(z ≤ 0. 82)  or p-value corresponding to z ≤ 0. 82 comes to be approximately 80%.

<h3>What is a z-score?</h3>

Z-score indicates how much a given value differs from the standard deviation.

z=\frac{x-\mu}{\sigma}

Where \mu = mean

\sigma=standard deviation

P(z ≤ 0. 82) means the p-value corresponding to z≤ 0. 82.

From the standard normal table

P(z ≤ 0. 82) ≈80%.

Hence, P(z ≤ 0. 82)  or p-value corresponding to z ≤ 0. 82 comes to be approximately 80%.

To get more about the z-score visit:

brainly.com/question/25638875

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(\sqrt{n}) = \frac{2.575*\sqrt{0.55*0.45}}{0.04}

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