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creativ13 [48]
2 years ago
10

Use the empirical rule to find a reasonable estimate for P(z ≤ 0. 82). 10% 30% 50% 80%.

Mathematics
1 answer:
o-na [289]2 years ago
3 0

P(z ≤ 0. 82)  or p-value corresponding to z ≤ 0. 82 comes to be approximately 80%.

<h3>What is a z-score?</h3>

Z-score indicates how much a given value differs from the standard deviation.

z=\frac{x-\mu}{\sigma}

Where \mu = mean

\sigma=standard deviation

P(z ≤ 0. 82) means the p-value corresponding to z≤ 0. 82.

From the standard normal table

P(z ≤ 0. 82) ≈80%.

Hence, P(z ≤ 0. 82)  or p-value corresponding to z ≤ 0. 82 comes to be approximately 80%.

To get more about the z-score visit:

brainly.com/question/25638875

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4 0
3 years ago
If a vertical line passes through a graph only once the relation is considered to be a function. True or false?
kotykmax [81]
This is True -----------
6 0
3 years ago
Read 2 more answers
PLZ HELP!!!!!!!!!!!!!!!!!!
goldfiish [28.3K]

Answer:

Step-by-step explanation:

The answer is C

4 0
3 years ago
Show both decimal places (5.06).
lilavasa [31]

a. the cost of a call for six minutes is 0.70.

b.the cost of a 14-minute call is 2.62.

c.the cost of a 9 ½2-minute call is 1.66.

<h3>How to find the cost of each call ?</h3>

given that

rate schedule for an m-minute call from any of its pay phones 0.70.

c(m) = 0.70 when m<=6

c(m) = 0.70+ 0.24(m-6) when m>6 & m is an integer

c(m) = 0.70+0.24((m-6)+1) when m>6 & m is not an integer.

a. to find the cost of a call for six minutes.

already given that c(m) =0.70 when m=6.

Therefore, the cost of a call for six minutes is 0.70.

b. to find the cost of a 14-minute call.

according to given information

c(14) = 0.70 + 0.24(m - 6) \\ c(14) = 0.70 + 0.24(14 \: - 6)  \\c(14) = 0.70 + (0.24 \times 14) - (0.24 \times 6) \\c(14) = 0.70 + (3.36 - 1.44) \\ c(14) = 0.70 + 1.92 \\ c(14) = 2.62

Therefore,the cost of a 14-minute call is 2.62.

c.to find the cost of a 9 ½2-minute call

according to given information

c(9  \frac{1}{2} 2) = 0.70 + 0.24((9 \frac{1}{2} 2 - 6) + 1) \\ c(9  \frac{1}{2} 2) = 0.70 + 0.24((9 - 6) + 1) \\ c(9  \frac{1}{2} 2) = 0.70 + 0.24(3+ 1) \\ c(9  \frac{1}{2} 2) = 0.70 + 0.24(4) \\ c(9  \frac{1}{2} 2) = 0.70 + 0.96 \\ c(9  \frac{1}{2} 2) = 1.66

Therefore,the cost of a 9 ½2-minute call is 1.66.

Learn more about problems on cost of call, refer:

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4 0
1 year ago
which order pair is a solution of the equation? y-4=7(x-6) A. only (5,4) B. only (6,5) C. both (5,4) and (6,5) D. neither​
Svet_ta [14]

Answer:

option D. Neither

Step-by-step explanation:

y-4=7(x-6)

using (5,4):

4-4=7(5-6)

0=7(-1)

0=-7

using (6,5):

5-4=7(6-6)

1=7(0)

1=0

so option D is the answer

6 0
3 years ago
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