Plz help I need help

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alex41 [277]

Answer:

thanks for free points.....

6 0

3 years ago

What’s the median of this data set ?

earnstyle [38]

Answer:

56

Step-by-step explanation:

The median is the middle number of a sorted set from least to greatest. After sorting the set 61, 48, 52, 65, 56, 77, 54 the set is 48, 52, 54, 56, 61, 65, 77.

The middle number in this set is 56 so the median is 56

3 0

3 years ago

Hello please help here!! thank you!!

Rudiy27

Answer:

x=110

Step-by-step explanation:

Since the sum of the interior angles of a trapazoid is 360, all you have to do is add the angles given and subtract that by 360, which gets you 110.

3 0

4 years ago

What is the exact value of arcsin(−2√2)

Svetach [21]

Answer:

π4;3π4

Step-by-step explanation: Trig table gives:

sinx=√22 --> arc x=π4

Unit circle gives another arc x that has the same sin value:

x=π−π4=3π4

3 0

4 years ago

Tim claims that a coin is coming up tails less than half of the time. In 110 tosses, the coin comes up tails 47 times. Using P-v

lilavasa [31]

Answer:

$z=\frac{0.427 -0.5}{\sqrt{\frac{0.5(1-0.5)}{110}}}=-1.531$

$p_v =P(z$

If we compare the p value obtained and using the significance level given $\alpha=0.1$ we have that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 10% of significance the proportion of tails is significantly less than 0.5.

Step-by-step explanation:

1) Data given and notation

n=110 represent the random sample taken

X=47 represent the number of tails obtained

$\hat p=\frac{47}{110}=0.427$ estimated proportion of tails

$p_o=0.5$ is the value that we want to test

$\alpha=0.1$ represent the significance level

Confidence=90% or 0.90

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the proportion of tails is lower than 0.5:

Null hypothesis: $p\geq 0.5$

Alternative hypothesis: $p < 0.5$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

3) Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.427 -0.5}{\sqrt{\frac{0.5(1-0.5)}{110}}}=-1.531$

4) Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.1$ . The next step would be calculate the p value for this test.

Since is a left tailed test the p value would be:

$p_v =P(z$

If we compare the p value obtained and using the significance level given $\alpha=0.1$ we have that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 10% of significance the proportion of tails is significantly less than 0.5.

6 0

3 years ago