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IceJOKER [234]
2 years ago
15

Plz help I need help

Mathematics
1 answer:
Alika [10]2 years ago
6 0

Answer:

5reeeStep-by-step explanation:

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What is the velocity in inches per second of a roll that has a speed of 140 rpm and a diameter of 2.4 cm?
fgiga [73]

Answer:

The velocity in the border of the roll is 0.025 m/s.

Step-by-step explanation:

We have a roll that has an angular velocity of

\omega = 140\, rpm

The tangent velocity (of the edge of the roll) can be calculated as

V=\omega * r=\omega * D/2\\\\V=(1/2)*140\frac{1}{min}*2.4\, cm*\frac{1m}{100cm}*\frac{1min}{60s}\\\\V=0.028\,m/s

The velocity in the border of the roll is 0.025 m/s.

8 0
4 years ago
Solve the proportion 4 : 16 = ? : 32 for the unknown, or in other words, 4 is to 16 as what number is to 32.
stiv31 [10]
In the proportion 4:16 =  x:32. The answer is 8
4 0
3 years ago
Please help with this question I will give points and brainliest thank you!
kramer

Answer:

that would be the middle ages

Step-by-step explanation:

6 0
3 years ago
Find the volume of the solid whose base is the circle x2+y2=25 and the cross sections perpendicular to the x-axis are triangles
ivanzaharov [21]

Triangles with height h and base b, with b=h have area \dfrac{b^2}2.

Such cross sections with the base of the triangle in the disk x^2+y^2\le25 (a disk with radius 5) have base with length

b(x)=\sqrt{25-x^2}-\left(-\sqrt{25-x^2}\right)=2\sqrt{25-x^2}

i.e. the vertical (in the x,y plane) distance between the top and bottom curves describing the circle x^2+y^2=25.

So when x=4, the cross section at that point has base

2\sqrt{25-16}=6

so that the area of the cross section would be 6^2/2 = 18.

In case it's relevant, the entire solid would have volume given by the integral

\displaystyle\int_{-5}^5\frac{b(x)^2}2\,\mathrm dx=4\int_0^5(25-x^2)\,\mathrm dx=\frac{1000}3

6 0
3 years ago
If x can be any number, how many solutions are there for the equation?
maw [93]
There are many solutions, and that's an understatement. There are actually an infinite number of solutions.
8 0
4 years ago
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