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3 years ago

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1 answer:

alex41 [277]3 years ago

6 0

Answer:

thanks for free points.....

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Write the following linear equation in function notation y=7x-2

BARSIC [14]

Answer:

The function notation is when we represent one of the coordinate points as a function of the other ones.

In the general case, we will have:

y = f(x)

Now, we have that:

y = 7*x - 2

Then the function notation will be:

y = f(x) = 7*x - 2

or simply

f(x) = 7*x - 2

4 0

3 years ago

Read 2 more answers

Factor completely. (HELP ASAP)

tamaranim1 [39]

-4k²(k+6)(k-1). The expression $-4k^{4}-20k^{3}+24k^{2}$ can be factored by factor completely to the expression -4k²(k+6)(k-1).

To factor the polynomial by factor completely, we must to use the pattern as follows:

1. Greatest Common Factor

$-4k^{4}-20k^{3}+24k^{2}$ factored into $-4k^{2}(k^{2}+5k-6)$

2. Factor the trinomial

$-4k^{2}(k+6)(k-1)$

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4 years ago

Factor $-2.8$ out of $-16.8m-11.2$ .

Talja [164]

-2.8(6m + 4) that is the answer

7 0

3 years ago

Find the derivative of the image below

Nata [24]

$~~~\dfrac{d}{dx} f(x) \\ \\=\dfrac{d}{dx} \left(x^3 \cdot \log_6 x \right)\\\\=x^3\dfrac{d}{dx} \left(\log_6 x\right) + \log_6 (x)\dfrac d{dx} x^3 \\\\=x^3 \cdot \dfrac 1{x \ln 6} + \log _6 (x) \cdot 3x^2\\\\=\dfrac{x^2}{\ln 6} + \log_6(x) \cdot 3x^2\\\\\\=x^2 \left(\dfrac 1{\ln 6} + 3\log_6 x \right)$

$\text{The derivative is now in a form of}~ x^A (B + C \log_D (x))$

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2 years ago

Jenny's mom is 36 years old. If Jenny's great-grandmother is 90 years old, what percent of Jenny's mother's age is Jenny's great

Serjik [45]

Answer:

The age of Jenny's mom is 40 % of age of Jenny's great-grandmother. (Input: 40)

Step-by-step explanation:

The percentage needed is calculated by the following expression:

$x = \frac{n_{M}}{n_{G}}\times 100\,\%$

Where:

$x$ - Percentage of Jenny's mother with respect to Jenny's great-grandmother, measured in percentage.

$n_{M}$ - Age of Jenny's mother, measured in years.

$n_{G}$ - Age of Jenny's great-grandmother, measured in years.

If we know that $n_{M} = 36\,yr$ and $n_{G} = 90\,yr$ , the percentage is:

$x = \frac{36\,yr}{90\,yr} \times 100\,\%$

$x = 40\,\%$

The age of Jenny's mom is 40 % of age of Jenny's great-grandmother.

3 0

4 years ago