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myrzilka [38]
3 years ago
5

What’s the median of this data set ?

Mathematics
1 answer:
earnstyle [38]3 years ago
3 0

Answer:

56

Step-by-step explanation:

The median is the middle number of a sorted set from least to greatest. After sorting the set 61, 48, 52, 65, 56, 77, 54 the set is 48, 52, 54, 56, 61, 65, 77.

The middle number in this set is 56 so the median is 56

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Jenna feeds her cat twice a day. She gives her cat 3/4 can of cat food each time. Jenna is having a friend take care of her cat
Anarel [89]

Given:

Number of times Jenna feeds her cat = 2

Cat food each time =\dfrac{3}{4}\text{ can}

Number of days = 5

Number of cans she bought = 8

To find:

Did Jenna buy enough cat food.

Solution:

Required food for each time  =\dfrac{3}{4}\text{ can}

Jenna feeds her cat twice a day.

Required food for a day =2\times \dfrac{3}{4}\text{ can}

                          =\dfrac{3}{2}\text{ can}

Required food for 5 days =5\times \dfrac{3}{2}\text{ can}

                           =\dfrac{15}{2}\text{ can}

                           =7.5\text{ can}

Since, 7.5 cans < 8 cans, therefore, Jenna buy enough cat food for her cat.

7 0
3 years ago
Help me! Will give 18 Points and will mark a person as brainiest to the first person who answers!
Reika [66]

Answer:

-201.1

-200.9

-200

201

201.8

Step-by-step explanation:

For the given statement we have come to know that number in the line who have negative vales are less than the positive value

so in the number line we can see that

-201.1 is negative value in the number line and it has least value so

next value is -200.9 who is also negative and least but greater than -201.1

moving towards next we can see the value of 200 who is also negative but greater than from -200.9 so moving towards next

we can see that 201.8 is positive value so it is greater from all the past values

next the value 201 is greater than 200

so after these explanation you can see that numbers moving from negative to positive values and its show greatest values as well

hope it will be brainliest to you .

thank you

4 0
3 years ago
The logistic equation for the population​ (in thousands) of a certain species is given by:
Eva8 [605]

Answer:

a.

b. 1.5

c. 1.5

d. No

Step-by-step explanation:

a. First, let's solve the differential equation:

\frac{dp}{dt} =3p-2p^2

Divide both sides by 3p-2p^2  and multiply both sides by dt:

\frac{dp}{3p-2p^2}=dt

Integrate both sides:

\int\ \frac{1}{3p-2p^2}  dp =\int\ dt

Evaluate the integrals and simplify:

p(t)=\frac{3e^{3t} }{C_1+2e^{3t}}

Where C1 is an arbitrary constant

I sketched the direction field using a computer software. You can see it in the picture that I attached you.

b. First let's find the constant C1 for the initial condition given:

p(0)=3=\frac{3e^{0} }{C_1+2e^{0} } =\frac{3}{C_1+2}

Solving for C1:

C_1=-1

Now, let's evaluate the limit:

\lim_{t \to \infty} \frac{3e^{3t} }{2e^{3t}-1 }  \\\\Divide\hspace{3}the\hspace{3}numerator\hspace{3}and\hspace{3}denominator\hspace{3}by\hspace{3}e^{3t} \\\\ \lim_{t \to \infty} \frac{3 }{2-e^{-3x}  }

The expression -e^{-3x} tends to zero as x approaches ∞ . Hence:

\lim_{t \to \infty} \frac{3e^{3t} }{2e^{3t}-1 } =\frac{3}{2} =1.5

c. As we did before, let's find the constant C1 for the initial condition given:

p(0)=0.8=\frac{3e^{0} }{C_1+2e^{0} } =\frac{3}{C_1+2}

Solving for C1:

C_1=1.75

Now, let's evaluate the limit:

\lim_{t \to \infty} \frac{3e^{3t} }{2e^{3t}+1.75 }  \\\\Divide\hspace{3}the\hspace{3}numerator\hspace{3}and\hspace{3}denominator\hspace{3}by\hspace{3}e^{3t} \\\\ \lim_{t \to \infty} \frac{3 }{2+1.75e^{-3x}  }

The expression -e^{-3x} tends to zero as x approaches ∞ . Hence:

\lim_{t \to \infty} \frac{3e^{3t} }{2e^{3t}+1.75 } =\frac{3}{2} =1.5

d. To figure out that, we need to do the same procedure as we did before. So,  let's find the constant C1 for the initial condition given:

p(0)=2=\frac{3e^{0} }{C_1+2e^{0} } =\frac{3}{C_1+2}

Solving for C1:

C_1=-\frac{1}{2} =-0.5

Can a population of 2000 ever decline to 800? well, let's find the limit of the function when it approaches to ∞:

\lim_{t \to \infty} \frac{3e^{3t} }{2e^{3t}-0.5 }  \\\\Divide\hspace{3}the\hspace{3}numerator\hspace{3}and\hspace{3}denominator\hspace{3}by\hspace{3}e^{3t} \\\\ \lim_{t \to \infty} \frac{3 }{2-0.5e^{-3x}  }

The expression -e^{-3x} tends to zero as x approaches ∞ . Hence:

\lim_{t \to \infty} \frac{3e^{3t} }{2e^{3t}-0.5 } =\frac{3}{2} =1.5

Therefore, a population of 2000 never will decline to 800.

6 0
3 years ago
Find VX<br> How do you solve this?
Alex_Xolod [135]
The length of VX equals to 80
Below I show my work of how I found the missing length.

To find the missing length, you pick the starting location. Then go in any direction and then do the same to the other side. Then write a ratio.

I decided to start at 46 and then go downward.

46/23=x/17

Then you cross multiply

43*17=x*23

782=23x

Divide 23 on both sides

X=34.

Then add 34 by 46 to get the length of VX.

Below is a picture of notes on how to solve these types of problems.

3 0
3 years ago
Please help me out… <br><br> Polygon ____ and polygon ____ are similar to polygon 1.
Masja [62]

Answer:

Polygon 3 and polygon 4 are similar to polygon 1.

Step-by-step explanation:

I believe this is the answer from the looks of it. If it's not 3, then try 2. I know one of them is definitely 4 though. I hope this helps!!

8 0
2 years ago
Read 2 more answers
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