What’s the median of this data set ?

Mathematics

1 answer:

earnstyle [38]3 years ago

3 0

Answer:

Step-by-step explanation:

The median is the middle number of a sorted set from least to greatest. After sorting the set 61, 48, 52, 65, 56, 77, 54 the set is 48, 52, 54, 56, 61, 65, 77.

The middle number in this set is 56 so the median is 56

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What is the area of a garden that measures 4mx4mx6mx4mx10mx8m

topjm [15]

The area of the garden is 120 square metre

<h2>Explanation:</h2>

The picture of the garden is shown below. In this problem, we have:

One square
Two rectangles

Recall that the area of a square is given by:

$A_{s}=L^2 \\ \\ A_{s}:Area \ of \ a \ square \\ L:Side \ of \ the \ square$

On the other hand, the area of a rectangle is given by:

$A_{r}=L_{1}\times L_{2} \\ \\ \\ A_{r}:Area \ of \ a \ rectangle \\ \\ L_{1}:Side \ 1 \ of \ the \ rectangle \\ \\ L_{2}:Side \ 2 \ of \ the \ rectangle$

Therefore:

FOR THE SQUARE:

$L=4m \\ \\ \\ Substituting \ values: \\ \\ \\ A_{s}=4^2 \\ \\ \boxed{A_{s}=16m^2}$

FOR THE RECTANGLE 1:

$L_{1}=6m \\ L_{2}=4m \\ \\ \\ Substituting \ values: \\ \\ \\ A_{r_{1}}=6(4) \\ \\ \boxed{A_{r_{1}}=24m^2}$

FOR THE RECTANGLE 2:

$L_{1}=10m \\ L_{2}=8m \\ \\ \\ Substituting \ values: \\ \\ \\ A_{r_{2}}=10(8) \\ \\ \boxed{A_{r_{2}}=80m^2}$

Finally, the area of a garden is the sum of the three areas:

$A_{total}=A_{s}+A_{r_{1}}+A_{r_{2}} \\ \\ A_{total}=16m^2+24m^2+80m^2 \\ \\ A_{total}=16+24+80 \\ \\ \boxed{A_{total}=120m^2}$

<h2>Learn more:</h2>

Area of a pizza: brainly.com/question/12878495

#LearnWithBrainly

4 0

3 years ago

What is the area of this figure?<br> 168<br> 102<br> 132<br> 340

JulsSmile [24]

Area of square =6*6= 36 cm^2
Area of trapezoid =1/2( base1+base2)*height
base 1=7
base2=21-6=15
height=6
Area of trapezoid =1/2( 7+15)*6= 66
whole area = area of square + area of trapezoid= 36+66=102
Answer 102

8 0

3 years ago

Arrange the steps in the correct order to express cos3x in terms of cosx cos(2x)cos(x)-sin(2x)(x) [1-sin^2(x)]cos(x)-[2sin(x)cos

noname [10]

cos(3x) = cos(2x+x)

= cos(2x) cos (x) -sin(2x)sin(x)

$=(1-2sin^2(x)) cos(x)-(2 sin(x) cos(x)) sin(x)$