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myrzilka [38]
3 years ago
5

What’s the median of this data set ?

Mathematics
1 answer:
earnstyle [38]3 years ago
3 0

Answer:

56

Step-by-step explanation:

The median is the middle number of a sorted set from least to greatest. After sorting the set 61, 48, 52, 65, 56, 77, 54 the set is 48, 52, 54, 56, 61, 65, 77.

The middle number in this set is 56 so the median is 56

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PLEASE HELP!!!!
OlgaM077 [116]

Answer: she will make $232.05 in 4 weeks.

Step-by-step explanation:

Since her profit is increasing by 10% each week, then the rate at which it is increasing is in geometric progression. The common ratio, r would be 110/100 = 1.1

We would apply the formula for determining the sum of n terms of a geometric progression which is expressed as

Sn = a(r^n - 1)/(r - 1)

Where

a represents the first term of the sequence.

r represents the common ratio.

n represents the number of terms(number of weeks)

From the information given,

a = 50

r = 1.1

n = 4 weeks

Therefore,

S4 = 50(1.1^4 - 1)/(1.1 - 1)

S4 = 50(1.1^4 - 1)/0.1

S4 = $232.05

5 0
4 years ago
Create an equivalent expression that includes a set of parentheses that make the value of the expression 13. Remember, you can h
Y_Kistochka [10]
47 is the answer Since two opposites add up to zero, remove them from the expression, and then you just add up the answers
4 0
3 years ago
Read 2 more answers
Which of the following cannot be used to state a postulate
sergij07 [2.7K]
A and C would be the correct answer
3 0
3 years ago
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an object is launched at 25 m/s from a height of 80 m. the equation for the height (h) in terms of time (t) is given by h(t)=4.9
Aneli [31]

There must be minus sign with 4.9 .

h(t) = -4.9t^2+25t +80

The given equation is the equation of parabola , which is maximum at its vertex, and the formula of vertex is

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So the height is maximum at t=2.55 seconds and to find the maximum height , we need to plug 2.55 for t , that is

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So the maximum height is 112 m .

3 0
3 years ago
Please answer this math
ohaa [14]
6 cm squared I believe
3 0
3 years ago
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