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PilotLPTM [1.2K]
2 years ago
10

Write an equation for the orbit of Saturn in the form x^2/a^2 + y^2/b^2 = 1

Mathematics
1 answer:
frozen [14]2 years ago
7 0

Answer:

  x²/2166784 +y²/2159989 = 1

Step-by-step explanation:

The relationship between the semi-axes and the eccentricity of an ellipse is ...

  e = √(1 -b²/a²)

In order to write the desired equation we need to find 'b' from 'e' and 'a'.

__

<h3>semi-minor axis</h3>

Squaring the equation for eccentricity gives ...

  e² = 1 -b²/a²

Solving for b², we have ...

  b²/a² = 1 -e²

  b² = a²(1 -e²)

<h3>ellipse equation</h3>

Using the given values, we find ...

  b² = 1472²(1 -0.056²) = 2166784(0.996864) ≈ 2159989

The desired equation is ...

  x²/2166784 +y²/2159989 = 1

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Solve for x 2 + 2 * x = 10
inysia [295]

Answer:

6

Step by step explanation:

2 + 2 * x = 10

2x+2=10

2x+2−2=10−2

Therefore, x = 6

7 0
3 years ago
Mason spent 15.85for 3 notebooks and 2 boxes of markers. the boxes of markers cost 3.95 each, and sales tax was 1.23. Mason also
Likurg_2 [28]
Multiply the amount of the notebooks which is 3, by the cost of the notebook, which is $15.85. that is $47.55. 

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$47.55 - 0.75 = $46.8
6 0
3 years ago
Read 2 more answers
What is the answer to f/3+4=8
Musya8 [376]

Answer:

so it would be f=36

Step-by-step explanation:

subtract 4 to the other side then multiply both sides by 3

4 0
3 years ago
An empty 5-gal water jug weighs 0.75 lb. With 3 c of water inside, the jug weighs 2.25 lb. Which equation models the jug's weigh
Deffense [45]
Weight of 1 c
3 c = 2.25 - empty bucket
3 c = 2.25 - 0.75
3 c = 1.5
c = 1.5/3 =1/2

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8 0
3 years ago
Perform a first derivative test on the function ​f(x)equals2 x cubed plus 3 x squared minus 120 x plus 6​; ​[minus5​,8​]. Bold
maria [59]

Answer:

a) Critical points

x = 4 and x = -5

b) x = 4 corresponds to a minimum point for the function f(x)

x = - 5 corresponds to a maximum point for the function f(x)

c) The minimum value of f(x) in the interval = -298

The maximum value of f(x) in the interval = 431;

Step-by-step explanation:

f(x) = 2x³ + 3x² - 120x + 6 in the interval [-5, 8]

a) To obtain the critical points, we need to obtain the first derivative of the function with respect to x. Because at critical points of a function, f(x), (df/dx) = 0

f'(x) = (df/dx) = 6x² + 6x - 120 = 0

6x² + 6x - 120 = 0

Solving the quadratic equation,

x = 4 or x = -5

The two critical points, x = 4 and x = -5 are in the interval given [-5, 8] (the interval includes -5 and 8, because it's a closed interval)

b) To investigate the nature of the critical points, we obtain f"(x)

Because f'(x) changes sign at the critical points

If f"(x) > 0, then it's a minimum point and if f"(x) < 0 at c, then it's a maximum point.

f"(x) = (d²f/dx²) = 12x + 6

at critical point x = 4

f"(x) = 12x + 6 = 12(4) + 6 = 54 > 0, hence, x = 4 corresponds to a minimum point.

at critical point x = -5

f"(x) = 12x + 4 = 12(-5) + 4 = -56 < 0, hence, x = -5 corresponds to a maximum point.

c) At x = 4,

f(x) = 2x³ + 3x² - 120x + 6 = 2(4)³ + 3(4)² - 120(4) + 6 = -298

At x = - 5

f(x) = 2x³ + 3x² - 120x + 6 = 2(-5)³ + 3(-5)² - 120(-5) + 6 = 431

7 0
2 years ago
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