Answer:
x ≈ ±20.086/√(t - 1)
Step-by-step explanation:
ln(t - 1) + ln(x²) = 6
Recall that lnu + lnv = ln(uv). Then
ln(t - 1) + ln(x²) = ln[(t-1)x²] = 6
Take the natural antilogarithm of each side
(t - 1)x² = e⁶
Divide each side by t - 1
x² = e⁶/(t-1)
Take the square root of each side
x = ±e³/√(t - 1)
x ≈ ±20.086/√(t - 1)
Answer:
the area of the top and bottom are 16 so the area of the left and right must be less than 16 in order to make it a true rectangle
The range is the set of all possible output, as you feed the function with all possible inputs. Since our inputs (domain) are -3, 0, 3, our outputs are
So, the range is