Answer:
20 students should be on each float
Step-by-step explanation:
Number of seniors = 100
Number of juniors = 80
To find number of students that should be on each float, find highest common factor (H.C.F) of 100 and 80
Write prime factorisation of 100 and 80.
100 =
× 
80 =
× 5
So,
H.C.F(100, 80) =
× 5 = 4 × 5 = 20
Therefore,
20 students should be on each float
Answer:
<h2>6 and 4</h2>
Step-by-step explanation:


Answer:
I believe that the reciprocal of -1
Hope this helps
Step-by-step explanation:
Answer:
3m² - 6
Step-by-step explanation:
Summing the 2 expressions
2m² + 3m - 4 + m² - 3m - 2 ← collect like terms
= (2m² + m²) + (3m - 3m) + (- 4 - 2)
= 3m² + 0 + (- 6) = 3m² - 6
Answer:
x=15
Step-by-step explanation:
Well, you have 2 numbers that sum up to 90 (the angle) so you can first minus the one you know, making your number from 90-30=60. Now all thats left is the 4x=60, which you can do 60/4=15 to get your answer that x=15.