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2 years ago

7

We have a part-whole ratio of 2 : 10. How can we represent this ratio as a percent?

2 answers:

Maurinko [17]2 years ago

6 0

Answer:

20%

Step-by-step explanation:

2:10 = 2/10 = 20/100 = 20%

madam [21]2 years ago

4 0

Since there’s a 10 multiple both sides by 10 and it gives you 20/100 which is 20%

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If 1 plus 4 = 5, 2+5 = 12, 3 plus 6=21 what does 5+8= ? I think 47

klio [65]

1 + 4 = 5, in this question, there is 1 "4", and 1 + 4 = 5

2 + 5 = 12, in this question, there are 2 "5", and 2 + 5 + 5 = 12

3 + 6 = 21, in this question, there are 3 "6", and 3 + 6 + 6 + 6 = 21

So for 5 + 8, there are 5 "8", so:

5 + 8 + 8 + 8 + 8 + 8 = 45

45 is your answer

hope this helps

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4 years ago

Read 2 more answers

one triangle on a graph has a vertical sise of 5 and horizontal side of 11. Another triangle on a graph has a vertical side of 1

Natasha_Volkova [10]

Yes because the triangle with the sides of 15 and 33 is just an enlarged triangle of the other one.

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3 years ago

valentinak56 [21]

Question:

The angle $\theta_1$ is located in Quadrant III, and $sin(\theta_1) = - \sqrt{\frac{3}{2}}$ .

What is the value of $cos(\theta_1)$ ?

Express your answer exactly. $cos(\theta1) =$ ________

Answer:

$cos(\theta_1) = - \frac{1}{2}$

Step-by-step explanation:

Given:

$sin(\theta_1) = - \sqrt{\frac{3}{2}}$

Since the angle $\theta_1$ is located in Quadrant III, we have:

$sin(\theta_1) = sin(\pi + \frac{\pi}{3})$

$\theta_1 = \pi + \frac{\pi}{3}$

$\theta_1 = \frac{4 \pi}{3}$

Thus, $cos(\theta_1)$ =

$cos(\theta_1) = cos(\pi + \frac{\pi}{3})$

$cos(\theta_1) = -cos(\frac{\pi}{3})$

$cos(\theta_1) = - \frac{1}{2}$

3 0

4 years ago

Which of the following is another way to express the equation 16 = -9 + z?

fenix001 [56]

D! all you have to do is switch the -9 and the z around! Good Luck!

6 0

3 years ago

Read 2 more answers

Xavier, Yvonne, and Zelda each try independently to solve a problem. If their individual probabilities for success are 1/4, 1/2

siniylev [52]

<u>Answer:</u> The probability that Xavier and Yvonne can solve a problem but Zelda cannot is $\frac{3}{64}$

<u>Step-by-step explanation:</u>

We are given:

Probability of success of Xavier, $P(S)_{Xavier}=\frac{1}{4}$

Probability of failure of Xavier, $P(F)_{Xavier}=1-\frac{1}{4}=\frac{3}{4}$

Probability of success of Yvonne, $P(S)_{Yvonne}=\frac{1}{2}$

Probability of failure of Yvonne, $P(F)_{Yvonne}=1-\frac{1}{2}=\frac{1}{2}$

Probability of success of Zelda, $P(S)_{Zelda}=\frac{5}{8}$

Probability of failure of Zelda, $P(F)_{Zelda}=1-\frac{5}{8}=\frac{3}{8}$

We need to calculate:

The probability that Xavier and Yvonne can solve the problem but Zelda cannot, we use:

$P(S)_{Xavier}\times P(S)_{Yvonne}\times P(F)_{Zelda}=\frac{1}{4}\times \frac{1}{2}\times \frac{3}{8}=\frac{3}{64}$

Hence, the probability that Xavier and Yvonne can solve a problem but Zelda cannot is $\frac{3}{64}$

6 0

3 years ago