20*15=300
It's "too short", but there's not much else to say here.
kilometers and miles are units used to measure distance.
1 mile is equal to 1.61 km
so if 1 mile is equivalent to 1.61 km
then to see how many kilometers are there in 50 miles we have to multiply 50 miles by 1.61 km/mile
therefore the number of km in miles is - 50 miles x 1.61 km/mile = 80.5 km
distance in km - 80.5 km
Do you mean the ratio 1:2
Answer:
a) 151lb.
b) 6.25 lb
Step-by-step explanation:
The Central Limit Theorem estabilishes that, for a random variable X, with mean
and standard deviation
, a large sample size can be approximated to a normal distribution with mean
and standard deviation
.
In this problem, we have that:

So
a) The expected value of the sample mean of the weights is 151 lb.
(b) What is the standard deviation of the sampling distribution of the sample mean weight?
This is 
Answer:
See explanation
Step-by-step explanation:
(4)
Using the sine ratio in the right triangle
sinΘ =
=
, thus
Θ =
(
) ≈ 51.1°
(5)
Using the tangent ratio in the right triangle
tanΘ =
=
, thus
Θ =
(
) ≈ 38.7°