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blagie [28]
2 years ago
8

Which plant is nonvascular? I didn't see an option for science so I chose math :^

Mathematics
1 answer:
vladimir1956 [14]2 years ago
4 0

Answer:

#4

These are the nonvascular plants or bryophytes (mosses, liverworts, and hornworts), the seedless vascular plants (clubmosses and ferns including, horsetails, club mosses, and whisk ferns), gymnosperms (conifers, cycads, Ginkgo, and gnetophytes), and angiosperms, or flowering plants.

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the king is having a sale where customers can buy 4 new tires for 419.96 what is the unit price of the tires
zlopas [31]

Answer:

you just do 419.96/4 which in this case equals 104.99

Step-by-step explanation:

7 0
3 years ago
WILL NAME BRAINLIEST PLEASE HELP ASAP!
PtichkaEL [24]
Important:  to denote exponentiation use " ^ ":

<span>(x + y)1 = ___ x + ___ y    NO
</span><span>(x + y)^1 = ___ x + ___ y   YES

(x+y)^1 = 1x + 1y

(x+y)^2 = 1x + 2xy + y^2

(x+y)^3 = 1x^3 + 3x^2*y + 3x*y^2 + y^3

and so on.   Look up "Pascal's Triangle" if you want more info on this pattern.

*******************

</span><span>(x + y)4 = ___ x4 + ___ x3y + ___ x2y2 + ___ xy3 + ___ y4    NO
</span>
<span>(x + y)^4 = ___ x^4 + ___ x^3y + ___ x^2y^2 + ___ xy^3 + ___ y^4    YES

 (x+y)^4 =  1x^4 + 4x^3*y + 6x^2*y^2 + 4x*y^3 + y^4</span>
7 0
4 years ago
Read 2 more answers
As part of a screening process, computer chips must be operated in an oven at 145 °C. Ten minutes after starting, the temperatur
Novosadov [1.4K]

Answer:

Step-by-step explanation:

I solved this using initial conditions and calculus, so I hope that's what you are doing in math.  It's actually NOT calculus, just a concept that is taught in calculus.

The initial condition formula we need is

y=Ce^{kt}

Filling in our formula with the 2 conditions we are given:

65=Ce^{10k}   and   85=Ce^{15k}

With those 2 equations, we have 2 unknowns, the C (initial value) and the k (the constant). We know that the initial value (or starting temp) for both conditions is the same, so we solve for C in one equation, sub it into the other equation and solve for k.  If

65=Ce^{10k} then

\frac{65}{e^{10k}}=C which, by exponential rules is the same as

C=65e^{-10k}

Since that value of C is the same as the value of C in the other equation, we sub it in:

85=65e^{-10k}(e^{15k})

Divide both sides by 65 and use the rules of exponents again to get

\frac{85}{65}=e^{-10k+15k} which simplifies down to

\frac{85}{65}=e^{5k}

Take the natural log of both sides to get

ln(\frac{85}{65})=5k

Do the log thing on your calculator to get

.2682639866 = 5k and divide both sides by 5 to find k:

k = .0536527973

Now that we have k, we sub THAT value in to one of the original equations to find C:

65=Ce^{10(.0536527973)}

which simplifies down to

65=Ce^{.536527973}

Raise e to that power on your calculator to get

65 = C(1.710059171) and divide to solve for C:

C = 38.01038064

Now sub in k and C to the final problem when t = 23:

y=38.01038064e^{(.0536527973)(23)} which simplifies a bit to

y=38.01038064e^{1.234014338}

Raise e to that power on your calculator to get

y = 38.01038064(3.434991111) and

finally, the temp at 23 minutes is

130.565

6 0
3 years ago
I need help please no need for step by step.
Klio2033 [76]
Sorry you dont have a picture so i can not help
4 0
2 years ago
Read 2 more answers
What is the inverse of y = x+3/4 ?<br><br> a. y=x-3/4<br> b. y=4x-3<br> c. y=4x+3<br> d. y= x-3/-4
viva [34]
Y = x + 3/4

x = y - 3/4

swap the variables:-

y = x - 3/4  (answer).   Its a.
4 0
4 years ago
Read 2 more answers
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