You need to find points where the line g(x) intercepts the quadratic function f(x) in one and only one point.
Then 3x^2 + 4x -2 = mx - 5
solve 3x^2 + 4x - mx -2 + 5 = 0
3x^2 + (4 - m)x + 3 = 0
In order to there be only one solution (one intersection point) the radicand of the quadratic formula must be 0 =>
b^2 - 4ac = (4 - m)^2 - 4(3)(3) = 0
(4 - m)^2 = 24
4 - m = +/- √(24)
m = 4 +/- √(24) = 4 +/- 2√(6)
Then m, the slope of the line, may be 4 + 2√6 and 4 - 2√6
A(b-c)=d solution is number 2. Attachment added
Answer:
125/12
Step-by-step explanation:
1st problem-no
2nd problem-yes
3rd problem-yes
4th problem-no
-6.5 which in your answer choices is a
It would be 3,000 as it is the next thousand. Since 2,641 is over 2,500 you can round to the next thousand 3,000
