Answer:
No, but i would like to know who they are
Step-by-step explanation:
HERE IS YOUR ANSWER...
I THINK THIS MAY SOLVE YOUR DOUBT....
THANK YOU......
You need to use a ratio of height (H) to shadow length (L) to solve the first problem. It's basically a use of similar triangles, with two perpendicular sides, and with the shadow making the same angle with the vertical.
6 ft = 72 ins, so that rH/L = 72/16 = 9/2 for the player.
So the bleachers are 9/2 x 6 ft = 27 ft.
For the second problem, 9 ft = 108 in, so that the ratio of the actual linear dimensions to the plan's linear dimensions are 9ft/(1/2in) = 2 x 108 = 216.
So the stage will have dimensions 216 times larger than 1.75" by 3".
That would be 31ft 6ins x 54ft.
Live long and prosper.
When you multiply 205 by 0.91 you get 186.55 and 205 minus 186.55 is 18.45
A: 7! and
<span>B: 5040
you only have 7 slots with 7 * 6 * 5 * 4 * 3 * 2 * 1</span>