52÷8=6.5
This is because 8 can go into 52, six times then your decimal pops up.
This is because 8 can go into 52, six times then your decimal pops up.
The length of an object object in feet is equal to 3 times it’s linked in yards the length of wall water side slide is 48 feet r
1 answer:
<h3><u>Question:</u></h3>
The length of an object in feet is equal to 3 times its length in yards. The length of a waterslide is 48 feet. Write and solve a multiplication equation to find the length of the waterslide in yards.
<h3><u>Answer:</u></h3>The length of waterslide is 16 yards
<h3><u>Solution:</u></h3>Given that,
The length of an object object in feet is equal to 3 times it’s length in yards
The length of wall water side slide is 48 feet
Let "y" be the length of object in yards
Write and solve a multiplication equation to find the length of the waterslides in yard
From given,
Length in feet = 3 times length in yards
<em><u>Therefore, the multiplication equation is:</u></em>
Solve the equation for "y"
Divide both sides of equation by 3
Thus length of waterslide is 16 yards
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Answer:
(-6, -5)
Step-by-step explanation:
Reflection across the y-axis leaves the point on the same horizontal line, but with the sign of its x-coordinate changed.
(x, y) ⇒ (-x, y) . . . . . reflection across the y-axis
(6, -5) ⇒ (-6, -5)
The image point is (-6, -5).
<h3>Answer: 24/25</h3>
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Explanation:
Sine is given to be negative, and so is tangent. This only happens in quadrant Q4
Recall that y = sin(theta), so if sin(theta) < 0, then we're below the x axis.
If tan(theta) < 0, then this means cos(theta) > 0
So we have y < 0 and x > 0 which places the angle somewhere in Q4.
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Draw a right triangle as shown below in the attached image. We have AC = 25 and BC = 7. Use the pythagorean theorem to find that AB = 24
So this is what your steps may look like
a^2+b^2 = c^2
7^2+b^2 = 25^2
b^2+49 = 625
b^2 = 625-49
b^2 = 576
b = sqrt(576)
b = 24
So because AB = 24, we know that the cosine of the angle is adjacent/hypotenuse = 24/25
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As an alternative, you could use the trig identity
sin^2(x) + cos^2(x) = 1
and plug in the given value of sine to solve for cosine. The cosine value result will be positive since we're in Q4.
So,
sin^2(x) + cos^2(x) = 1
(-7/25)^2 + cos^2(x) = 1
(49/625) + cos^2(x) = 1
cos^2(x) = 1 - (49/625)
cos^2(x) = (625/625) - (49/625)
cos^2(x) = (625-49)/625
cos^2(x) = 576/625
cos(x) = sqrt(576/625)
cos(x) = sqrt(576)/sqrt(625)
cos(x) = 24/25
This is effectively a rephrasing of the previous section since the pythagorean trig identity is more or less the pythagorean theorem (just in a trig form)