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svetoff [14.1K]
2 years ago
8

What is the distance between points L(-1,3) and 2(4, -9) HELP ASAP

Mathematics
2 answers:
sleet_krkn [62]2 years ago
6 0

Step-by-step explanation:

the other answer is correct.

just a few words about the why :

when you look at 2 points on the coordinate grid, then the distance between them creates a right-angled triangle.

the direct distance is the Hypotenuse (the baseline opposite of the 90° angle).

and the x-coordinate difference and the y-coordinate difference are the legs of that triangle.

and then we can use Pythagoras

c² = a² + b²

c = sqrt(a² + b²)

with c being the Hypotenuse.

and you see, that is exactly the so-called distance formula the other answer used.

Reika [66]2 years ago
5 0

Answer:

13 units

Step-by-step explanation:

calculate the distance d using the distance formula

d = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2    }

with (x₁, y₁ ) = (- 1, 3 ) and (x₂, y₂ ) = (4, - 9 )

d = \sqrt{(4-(-1))^2+(-9-3)^2}

  = \sqrt{(4+1)^2+(-12)^2}

   = \sqrt{5^2+144}

   = \sqrt{25+144}

   = \sqrt{169}

   = 13

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qwelly [4]
You can tell that the right angled triangle to the left is in fact the part which is missing from the rectangle at the top.

Area

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5 0
3 years ago
Read 2 more answers
Evaluate Cot0 if sin0= square root of 6/5
Lina20 [59]
To evaluate cot θ given that sinθ=√6/5 we shall have:
sin θ=opposite/hypotenuse
hence
opposite=√6
hypotenuse=5
thus the adjacent will be found using the Pythagorean theorem
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plugging in the value we get:
5²=(√6)²+b²
b²=25-6
b²=19
b=√19
thus
adjacent=√19
but
cotθ=1/tanθ
tanθ=√6/√19
hence:
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6 0
3 years ago
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Illusion [34]

Answer:

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Step-by-step explanation:

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IRISSAK [1]

Answer:

D

Step-by-step explanation:

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8 0
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beks73 [17]
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