9514 1404 393
Answer:
x-intercept: (16, 0)
y-intercept: (0, 8)
Step-by-step explanation:
Each intercept is found by setting the other variable to zero and solving for the variable of interest.
I like to find the intercepts from this form because it basically involves dividing the constant by the variable coefficient.
<u>x-intercept</u>
y = 0, so we have 4x = 64 ⇒ x = 64/4 = 16
x-intercept is (16, 0)
<u>y-intercept</u>
x = 0, so we have 8y = 64 ⇒ y = 64/8 = 8
y-intercept is (0, 8)
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<em>Additional comment</em>
There is a form of the linear equation called the "intercept form" that looks like this:
x/a +y/b = 1
where 'a' is the x-intercept and 'b' is the y-intercept.
You can get this form by dividing the standard form equation by the constant. Here, that gives ...
4x/64 +8y/64 = 1
x/16 +y/8 = 1
This is nice because it gives both intercepts with one operation (divide by the constant). It's easy enough to do, but not always easy to explain. This form of the equation of a line is rarely seen.
Answer:
The machine caps 900 bottles in 45 seconds
Step-by-step explanation:
15/300 is equal to 45/900
Answer:
1 out of every 3 races could be won by Rachelle
Step-by-step explanation:
Answer:
Σ(-1)^kx^k for k = 0 to n
Step-by-step explanation:
The nth Maclaurin polynomials for f to be
Pn(x) = f(0) + f'(0)x + f''(0)x²/2! + f"'(0)x³/3! +. ......
The given function is.
f(x) = 1/(1+x)
Differentiate four times with respect to x
f(x) = 1/(1+x)
f'(x) = -1/(1+x)²
f''(x) = 2/(1+x)³
f'''(x) = -6/(1+x)⁴
f''''(x) = 24/(1+x)^5
To calculate with a coefficient of 1
f(0) = 1
f'(0) = -1
f''(0) = 2
f'''(0) = -6
f''''(0) = 24
Findinf Pn(x) for n = 0 to 4.
Po(x) = 1
P1(x) = 1 - x
P2(x) = 1 - x + x²
P3(x) = 1 - x+ x² - x³
P4(x) = 1 - x+ x² - x³+ x⁴
Hence, the nth Maclaurin polynomials is
1 - x+ x² - x³+ x⁴ +.......+(-1)^nx^n
= Σ(-1)^kx^k for k = 0 to n