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aleksandr82 [10.1K]
3 years ago
10

(x+y) ²+(x-y)²+(x+y)*(x-y)​

Mathematics
1 answer:
goldfiish [28.3K]3 years ago
8 0
3x^2+y^2
That’s the answer so you should be good!!!
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ITS A BIT BLURRY BUT IT WORKS SOMEONE PLEASE GET THIS DONE IN THE NEXT FEW MINUTES ILL MARK BRAINLIEST
ZanzabumX [31]

Answer:

a) m∠T

b) line W and line Z

c) ∠ZTU

d) ∠YTX

e) 90° or m∠5

f) m∠1 and m∠2

g) m∠2

h) 180° or m∠1 & m∠5 or m∠2 & m∠3 & m∠4

i) line WTY and line YTX

j) the angle bisector U

Step-by-step explanation:

5 0
3 years ago
What solid figure is this
amid [387]

Answer: Trapezoidal prism

A figure with 4 sides and a parallel side is called a trapezoid, this is a 3 dimentional trapezoid which is called a trapezoidal prism.

7 0
3 years ago
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Container A- each side of the prism will measure 2 inches, and the height will be 10 inches. Container B- each side of the prism
vesna_86 [32]

Answer:

What is this question asking

Step-by-step explanation:

3 0
3 years ago
The table shows the number of cups of water required when cooking different amounts of rice.
Harman [31]

<u>Answer-</u>

<em>The amount of water is the dependent value.</em>

<u>Solution-</u>

Plotting the graph from the given data points, it comes out to be a straight line with positive slope. So, both the variables i.e amount of rice and amount of water are in a linear relationship. They are directly proportional to each other.

As the amount of rice increases, the water needed to cook the rice also increases. Plotting a graph taking amount of rice in abscissa and amount of water in ordinate, a straight line was obtained.

Here, amount of rice is the independent variable and amount of water is dependent variable as it depends on the amount of rice.

3 0
3 years ago
If a tank holds 5000 gallons of water, which drains from the bottom of the tank in 40 minutes, then Torricelli's Law gives the v
pochemuha

Answer:

V'(t) = -250(1 - \frac{1}{40}t)

If we know the time, we can plug in the value for "t" in the above derivative and find how much water drained for the given point of t.

Step-by-step explanation:

Given:

V = 5000(1 - \frac{1}{40}t )^2  , where 0≤t≤40.

Here we have to find the derivative with respect to "t"

We have to use the chain rule to find the derivative.

V'(t) = 2(5000)(1 - \frac{1}{40} t)d/dt (1 - \frac{1}{40}t )

V'(t) = 2(5000)(1 - \frac{1}{40} t)(-\frac{1}{40} )

When we simplify the above, we get

V'(t) = -250(1 - \frac{1}{40}t)

If we know the time, we can plug in the value for "t" and find how much water drained for the given point of t.

4 0
4 years ago
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