Hi there!
The question gives us the quadratic equation , and it tells us to solve it using the quadratic formula, which goes as . However, we must first find the values of a, b, and c. The official quadratic equation goes as , which matches the format of the given quadratic equation. Hence, the value of a would be 1, the value of b would be 5, and the value of c would be 3. Now, just plug it back into the quadratic equation and simplify to get the zeros of the equation.
x = \frac{-b \pm \sqrt{b^2 - 4ac} }{2a}
x = \frac{-(5) \pm \sqrt{(5)^2 - 4(1)(3)} }{2(1)}
x = \frac{-5 \pm \sqrt{25 - 12} }{2}
x = \frac{-5 \pm \sqrt{13} }{2}
x = \frac{-5 \pm 3.61 }{2}
x = \frac{-5 + 3.61 }{2}, x = \frac{-5 - 3.61 }{2}
x=-0.695 \ \textgreater \ \ \textgreater \ -0.7, x= -4.305 \ \textgreater \ \ \textgreater \ x=-4.31
Therefore, the solutions to the quadratic equation are x = -0.7 and x = -4.31. Hope this helped and have a phenomenal day!
Your answer is 4.31
The origin (0,0) is not in the shaded region and the shaded region is above the line because of the (>) greater then sign
Answer:
x = 30 degrees
Step-by-step explanation:
cos (x) = sqrt(3)/2
We need to take the inverse of each side
cos ^-1( cos x) = cos ^-1 (sqrt(3)/2)
x = cos ^-1 (sqrt(3)/2)
x = 30 degrees
The life expectancies of residents of a country for which the average annual income is $80,000 for the three models are 12309.9352, 172.2436 and 4828.1393
The life expectancies of the models are given as:
--- model 1
--- model 2
--- model 3
Given that the average annual income is $80,000;
We simply substitute 80000 for income in the equations of the three models.
So, we have:
<u>Model 1</u>
<u>Model 2</u>
<u>Model 3</u>
Hence, the life expectancies are 12309.9352, 172.2436 and 4828.1393
Read more about linear models at:
brainly.com/question/8609070
Line segment of length k is divided into 3 equal parts.
so first segment is 0-k/3 and third segment is 2/3k-k
so mid-pt of 1st = k/6 and 3rd = 5/6k
so the distance in between = 5/6k-k/6 = 4/6k = 2/3k
ans is A
