Question

The length of a rectangle is 2 units shorter than one-fifth of the width, x.

Answer 1

perimeter = 2L+2w

from the problem L = 1/5w-2

so perimeter = 2(1/5w-2) +2w

= 2/5w-4 +2w

=12/5w-4

without seeing your choices it should be similar to this

Answer 2

Answer:

Perimeter = $\frac{12x}{5}-4$

Step-by-step explanation:

Let the length of a rectangle is l and width is w.

Then the expression which represents the perimeter is

P = 2(l + w)

It is given in the question length of the rectangle = l and width = x

and l = $\frac{x}{5}-2$

By replacing these values in the expression for the perimeter

P = $2[\frac{x}{5}-2+x]$

  = $2[\frac{6x}{5}-2]$

  = $\frac{12x}{5}-4$

Therefore, expression that represents the perimeter of the rectangle will be

Perimeter = $\frac{12x}{5}-4$