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AVprozaik [17]
3 years ago
11

Please answer the question now in two minutes

Mathematics
1 answer:
oksian1 [2.3K]3 years ago
6 0

Answer:

Coordinates of point P is (-14,3).

Step-by-step explanation:

Given that mid point of line segment \overline {PQ} is at <em>M(-9, 8.5).</em>

Q is at <em>(-4, 14)</em>.

Let coordinate of P be (x,y).

Using the ratio, we can say the following:

<em>The coordinates of mid point</em> (X,Y) of a line with endpoints (x_1, y_1) and (x_2, y_2) is given as:

X=\dfrac{(x_1+ x_2)}{2}

Y=\dfrac{(y_1+ y_2)}{2}

Using the formula for above given dimensions:

-9 =\dfrac{x+(-4)}{2}\\\Rightarrow x = -18+4 = -14

8.5=\dfrac{(14+ y)}{2}\\\Rightarrow y = 17-14 =3

So, the <em>coordinates of point P are</em> (-14,3).

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Using the binomial distribution, it is found that there is a 0.81 = 81% probability that NEITHER customer is selected to receive a coupon.

For each customer, there are only two possible outcomes, either they receive the coupon, or they do not. The probability of a customer receiving the coupon is independent of any other customer, which means that the binomial distribution is used to solve this question.

Binomial probability distribution

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

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In this problem:

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The probability that <u>neither receives a coupon is P(X = 0)</u>, thus:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{2,0}.(0.1)^{0}.(0.9)^{2} = 0.81

0.81 = 81% probability that NEITHER customer is selected to receive a coupon.

A similar problem is given at brainly.com/question/25326823

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