Answer:
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The best answer that describes the relationship between the rate of change with respect to time of the pressure and the rate of change with respect to time t of the volume is; dP/dt = (-k/V²)(dV/dt)
We are given;
p = k/v
Thus if we cross multiply, we will get;
PV = k
Where;
P is pressure
V is volume
k is a constant
- Using the product rule of differentiation on both sides with respect to time t gives;
V(dP/dt) + P(dV/dt) = 0
This is because k is a constant.
Putting k/v for P gives;
V(dP/dt) + (k/V)(dV/dt) = 0
>> V(dP/dt) = - (k/V)(dV/dt)
Divide both sides by V by division property of equality to get;
dP/dt = (-k/V²)(dV/dt)
Read more about Boyles' law at; brainly.com/question/1696010
It’s b.
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Answer:
an ion
Explanation:
- When an atom gains/loses an electron, the atom becomes charged, and is called an ion.
- Gaining an electron results in a negative charge, so the atom is an anion.
- Losing an electron results in a positive charge, so the atom ion is a cation.
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