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inysia [295]
3 years ago
11

Classify each of the following as a molecular, an ionic, a network, or a metallic solid by matching a substance on the left with

a description on the right. Clear All dry ice (CO2) lime (CaO) gold bar (Au) sand (SiO2) Molecular Ionic Network Metallic
Chemistry
1 answer:
artcher [175]3 years ago
4 0

Answer:

Sand - A network

Dry Ice - Molecule

Lime - Ionic

Gold bar - Metallic

Explanation:

The items are;

dry ice (CO2)

lime (CaO)

gold bar (Au)

sand (SiO2)

The options are;

molecular,

an ionic,

a network,

or a metallic solid

Among the items, the only metal present is the gold bar. So it makes sense that the gold bar is matched with 'Metallic solid'.

The Calcium oxide is an 'ionic' compound as it contains the calcium ion and the oxygen ion bonded by an electrovalent bond.

Dry Ice, CO2 is a molecule composed of one carbon atom bonded to two oxygen atoms via two double bonds. So it is matched with 'Molecular'

The only option left is 'A network' and it is matched with Sand (SiO2).

The result is given as;

Sand - A network

Dry Ice - Molecule

Lime - Ionic

Gold bar - Metallic

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The teacher prepares 2.50 liters (l) of a salt solution for a class experiment. how many quarts (qt) are in 2.50 l? (1 l =1.06 q
trasher [3.6K]

The teacher prepares 2.50 liters (l) of a salt solution for a class experiment, in this quantity 2.65 quartz are present.

<h3>What is conversion factor?</h3>

Conversion factor is a quantity which will be multiplied or divide with any other measurement for the conversion of that measurement.

Given that quantity of salt solution = 2.50 L

We know that, 1 L = 1.06 qt

Here conversion factor is 1.06 qt/L as it will be multiplied on given measurement to convert into quartz as:

2.50L = 2.50L × 1.06qt/L = 2.65qt

Hence required value is 2.65qt.

To know more about conversion factor, visit the below link:

brainly.com/question/97386

4 0
2 years ago
How many grams of MgCl2 will be obtained when 435 mL of 0.300 M HCl react with an excess of Mg(OH)2?
Marina CMI [18]
The grams of Mg(OH)2 produced is calculated as below

calculate the moles of HCl produced =molarity  xvolume/1000

= 0.3 x 435/1000= 0.1305 moles

write the equation for reaction
Mg(OH)2 +2HCl = MgCl2 + 2H2O

by use of mole ratio between HCl :MgCl2  which is 2 :1  the  moles of HCl =  0.1305 x1/2 =0.0653  moles of MgCl2

mass of MgCl2 = moles x molar mass

= 0.0653mol x95 g/mol = 6.204  grams of MgCl2
3 0
3 years ago
How many moles of oxygen are needed to react completely with 17.2 moles of aluminum
Butoxors [25]

Answer:As you have asked, I will not do your homework for you but will outline the reasoning…

Find out the atomic weight of all the species involved in the problem. Three decimals is more than sufficient.

Look at the periodic table of the elements and other resources (notes!) as necessary to determine the expected valence of the species

Once you know how many of these go with those, you are cruising…

You already know that  4Al+3O2→2Al2O3

So, you are in a great position to determine the number of moles of  O2 , as you know you have 14.8 mol of Al and the ratio of combination is always 4 molecules.

Explanation:

4 0
2 years ago
If 2.0×10−4 moles of S2O2−8 in 170 mL of solution is consumed in 170 seconds , what is the rate of consumption of S2O2−8?
Ostrovityanka [42]

Answer : The rate of consumption of S_2O_2^{-8} is, 7.0\times 10^{-6}M/s

Explanation : Given,

Moles of S_2O_2^{-8} = 2.0\times 10^{-4}mol

Volume of solution = 170 mL = 0.170 L     (1 L = 1000 mL)

Time = 170 s

First we have to calculate the concentration.

\text{Concentration}=\frac{\text{Moles}}{\text{Volume of solution}}

\text{Concentration}=\frac{2.0\times 10^{-4}mol}{0.170L}

\text{Concentration}=1.2\times 10^{-3}M

Now we have to calculate the rate of consumption.

\text{Rate of consumption}=\frac{\text{Concentration}}{\text{Time}}

\text{Rate of consumption}=\frac{1.2\times 10^{-3}M}{170s}

\text{Rate of consumption}=7.0\times 10^{-6}M/s

Thus, the rate of consumption of S_2O_2^{-8} is, 7.0\times 10^{-6}M/s

8 0
3 years ago
Write a balanced chemical equation for the decomposition of RbNO3.<br><br>Help me please!!!​
nalin [4]

Answer:

<u>2RbNO³ --> 2Rb + N² + 30²</u>

Hope this helps!

8 0
3 years ago
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