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777dan777 [17]
3 years ago
5

The broadest taxonomic group for classifying living organisms is the blank

Chemistry
1 answer:
zloy xaker [14]3 years ago
5 0

Answer:

Domain

Explanation:

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Which factor most influenced the economic
Vikki [24]

It was by far "warm and wet growing seasons" that was the most important factor in terms of the South's economic development. Cotton and tobacco were the biggest exports.

Explanation:

These crops created tons of cash, had massive markets round the world, however required a stable and enormous hands to grow and harvest them.The yank South is understood for its long, hot summers, and wealthy soils in stream valleys creating it a perfect location for growing cotton. the various southern seaports and riverside docks allowed shipping cotton to remote destinations. By 1860, Southern plantations equipped seventy fifth of the world's cotton, with shipments from Houston, city, Charleston, Mobile, Savannah, and some different ports. The unquenchable European demand for cotton was a results of the commercial Revolution that created the machinery and factories to method raw cotton into vesture that was higher and cheaper than hand-made product.

6 0
4 years ago
Read 2 more answers
C4H8(g)⟶2C2H4(g) C4H8(g)⟶2C2H4(g) has an activation energy of 262 kJ/mol.262 kJ/mol. At 600.0 K,600.0 K, the rate constant, ????
Yanka [14]

Answer:

Rate constant at 725 K is 5.2\times 10^{-4}s^{-1}

Explanation:

According to Arrhenius equation for a reaction-

ln(\frac{k_{2}}{k_{1}})=\frac{E_{a}}{R}(\frac{1}{T_{1}}-\frac{1}{T_{2}})

where k_{2} and k_{1} are rate constants of reaction at T_{2} and T_{1} temperatures (in kelvin) respectively.

E_{a} is activation energy of reaction.

Here T_{1}= 600 K , k_{1}= 6.1\times 10^{-8}s^{-1}

T_{2}= 725 K, E_{a}= 262 kJ/mol and R = 8.314 J/(mol.K)

So plugin all the values in the above equation-

ln(\frac{k_{2}}{6.1\times 10^{-8}s^{-1}})=\frac{262\times 10^{3}J/mol}{8.314J/(mol.K)}\times (\frac{1}{600K}-\frac{1}{725K})

So, k_{2} = 5.2\times 10^{-4}s^{-1}

Hence rate constant at 725 K is 5.2\times 10^{-4}s^{-1}

7 0
4 years ago
When sodium metal is added to water, an orange flame is observed on the metal surface. Based on this observation, what can best
pickupchik [31]
All you can conclude is that something must be burning with an orange flame.

Actually, the "something" that must be burning is the hydrogen that is produced when the sodium reacts with the water:

2Na + 2H₂O → 2NaOH + H₂ + heat

So much heat is produced that the hydrogen catches fire and some of the sodium evaporates into the flame.

The electrons in the sodium atoms get "excited" in the flame. When they drop back to a lower energy level, they emit energy in the form of an orange-yellow light.
3 0
4 years ago
If the mass of a block of wood is 4.6g and the density is 0.98g/mL what is the volume.
irina [24]

Answer:

The answer is

<h2>4.69 mL</h2>

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

volume =  \frac{mass}{density}  \\

From the question

mass of wood = 4.6 g

density = 0.98 g/mL

It's volume is

volume =  \frac{4.6}{0.98}  \\  = 4.69387755...

We have the final answer as

<h3>4.69 mL</h3>

Hope this helps you

3 0
4 years ago
A volume of 60.0 mL of a 0.120 M HNO3 solution is titrated with 0.840 M KOH. Calculate the volume of KOH required to reach the e
german

Answer: 8.57 ml of KOH is required to reach the equivalence point.

Explanation:

To calculate the volume of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HNO_3

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is KOH.

We are given:

n_1=1\\M_1=0.120M\\V_1=60.0mL\\n_2=1\\M_2=0.840M\\V_2=?

Putting values in above equation, we get:

1\times 0.120\times 60.0=1\times 0.840\times V_2\\\\V_2=8.57mL

Thus 8.57 ml of KOH is required to reach the equivalence point.

8 0
4 years ago
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