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evablogger [386]
3 years ago
14

Rutherford and his colleagues fired a beam of small, positively charged alpha particles at thin gold foil. Some of these alpha p

articles were deflected at angles as they passed through the foil.
What conclusion did Rutherford and his colleagues draw from their results?
A) The atom must contain some neutral charge spread throughout the atom. He called these particles neutrons.
B) The atom must contain some centrally located negative charge. He called this core of negative charge the nucleus.
C) The atom must contain some centrally located positive charge. He called this core of positive charge the nucleus.
D) Thomson's plum pudding model of the atom was correct. The atom contains positive charge spread throughout its structure.
Chemistry
1 answer:
horsena [70]3 years ago
7 0

C) The atom must contain some centrally located positive charge. He called this core of positive charge the nucleus.

Explanation:

Rutherford concluded from his experiment that the atom contains some centrally located positive charge. He called the core the nucleus.

Rutherford developed the nuclear model of the atom.

  • In a bid to explain his observation, Rutherford suggested the nuclear model.
  • The model consists of small positively charged center called the nucleus.
  • Nearly all the mass is concentrated in the nucleus.
  • The extranuclear space is made up of electrons orbiting the nucleus.

Learn more:

Rutherford brainly.com/question/1859083

#learnwithBrainly

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Which statement describes how heat is transferred by radiation?
lara31 [8.8K]

Answer:

Its Convention Current Waves i think

4 0
3 years ago
Read 2 more answers
Different isotopes of the same element emit light at slightly different wavelengths. A wavelength in the emission spectrum of a
Inessa [10]

Different isotopes of the same element emit light at slightly different wavelengths, the minimum number of slits  is mathematically given as

N=1820slits

<h3>What minimum number of slits is required to resolve these two wavelengths in second-order?</h3>

Generally, the equation for the wave is mathematically given as

d\ sin\ (\theta\ m) \ = \ m\  \lambda

Where the chromatic resolving power (R) is defined by

R\  =\ \lambda\ / \ d \  \lambda

R = nN,

Therefore

\lambda_1 \ = \  (656.45)(1 \ * \ 10^{-9})/1mm

\lambda_1= 656.45*10^{-9}

and

\lambda_2= (656.27)(1*10^{-9})/1mm

\\\\\lambda_2= 656.27*10^{-9}m

In conclusion, the minimum number of slits is required to resolve these two wavelengths in second-order

N\ =\ \dfrac{\lambda}{m\ d\ T\ }\\\\

Therefore

N\ =\ \dfrac{656.45 \ * \ 10^{-9}}{2\ * \ (0.18*10^{-9})}

N=1820slits

Read more about slits

brainly.com/question/24305019

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7 0
2 years ago
Hydrogen has three isotopes 1H, 2H, and 3H. What is the difference between these three isotopes?
Leona [35]
The main difference between the 3 isotopes of hydrogen are the number of neutrons in the nucleus. Hydrogen has no neutrons, Deuterium has one neutron, and tritium has two neutrons. All three have one proton and one electron.
4 0
2 years ago
Can somebody help me, please!
zavuch27 [327]

Answer:

Rubidium-85=61.2

Rubidium-87=24.36

Atomic Mass=85.56 amu

Explanation:

To find the atomic mass, we must multiply the masses of the isotope by the percent abundance, then add.

<u>Rubidium-85 </u>

This isotope has an abundance of 72%.

Convert 72% to a decimal. Divide by 100 or move the decimal two places to the left.

  • 72/100= 0.72      or        72.0 --> 7.2 ---> 0.72

Multiply the mass of the isotope, which is 85, by the abundance as a decimal.

  • mass * decimal abundance= 85* 0.72= 61.2

Rubidium-85=61.2

<u>Rubidium-87</u>

This isotope has an abundance of 28%.

Convert 28% to a decimal. Divide by 100 or move the decimal two places to the left.

  • 28/100= 0.28       or        28.0 --> 2.8 ---> 0.28

Multiply the mass of the isotope, which is 87, by the abundance as a decimal.

  • mass * decimal abundance= 87* 0.28= 24.36

Rubidium-87=24.36

<u>Atomic Mass of Rubidium:</u>

Add the two numbers together.

  • Rb-85 (61.2) and Rb-87 (24.36)
  • 61.2+24.36=85.56 amu
4 0
3 years ago
A hot air balloon is filled to 1250 m3 at 27 C. At what temperature will the balloon be filled to 1600 m3 if the pressure remain
SSSSS [86.1K]

Answer:

384.2 K

Explanation:

First we convert 27 °C to K:

  • 27 °C + 273.16 = 300.16 K

With the absolute temperature we can use <em>Charles' law </em>to solve this problem. This law states that at constant pressure:

  • T₁V₂=T₂V₁

Where in this case:

  • T₁ = 300.16 K
  • V₂ = 1600 m³
  • T₂ = ?
  • V₁ = 1250 m³

We input the data:

300.16 K * 1600 m³ = T₂ * 1250 m³

And solve for T₂:

T₂ = 384.2 K

7 0
3 years ago
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