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2 years ago

PLEASE HELP ME PLEASE :(

Mathematics

1 answer:

steposvetlana [31]2 years ago

8 0

Answer:

Vertical line of symmetry, from midpoint of top to midpoint of bottom

Horizontal line of symmetry, from midpoint on left to midpoint on right.

Rotational line of symmetry on the two diagonals.

Step-by-step explanation:

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Help me PLEASEEEEE I need help

V125BC [204]

Answer: maybe 18.6 °F?

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2 years ago

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2. "

Lesechka [4]

Answer:

In a quadrilateral, the two pairs of opposite angles are congruent. One of the properties of any quadrilateral is that the opposite angles must be congruent.

Step-by-step explanation:

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3 years ago

What is 7/10 + 7/10 =

Nonamiya [84]

The correct answer is 1.4 or 1 4/10

I did this by turning 7/10 into a decimal which is 0.7.

Now I just add 0.7 + 0.7.

For that equation i got 1.4

This would equal 1 4/10

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3 years ago

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Use the surface integral in Stokes' Theorem to calculate the circulation of the field Bold Upper F equals x squared Bold i plus

Alinara [238K]

Answer:

The circulation of the field f(x) over curve C is Zero

Step-by-step explanation:

The function $f(x)=(x^{2},4x,z^{2})$ and curve C is ellipse of equation

$16x^{2} + 4y^{2} = 3$

Theory: Stokes Theorem is given by:

$I= \int \int\limits {{Curl f\cdot \hat{N }} \, dx$

Where, Curl f(x) = $\left[\begin{array}{ccc}\hat{i}&\hat{j}&\hat{k}\\\frac{∂}{∂x} &\frac{∂}{∂y} &\frac{∂}{∂z} \\F1&F2&F3\end{array}\right]$

Also, f(x) = (F1,F2,F3)

$\hat{N} = grad(g(x))$

Using Stokes Theorem,

Surface is given by g(x) = $16x^{2} + 4y^{2} - 3$

Therefore, tex]\hat{N} = grad(g(x))[/tex]

$\hat{N} = grad(16x^{2} + 4y^{2} - 3)$

$\hat{N} = (32x,8y,0)$

Now, $f(x)=(x^{2},4x,z^{2})$

Curl f(x) = $\left[\begin{array}{ccc}\hat{i}&\hat{j}&\hat{k}\\\frac{∂}{∂x} &\frac{∂}{∂y} &\frac{∂}{∂z} \\F1&F2&F3\end{array}\right]$

Curl f(x) = $\left[\begin{array}{ccc}\hat{i}&\hat{j}&\hat{k}\\\frac{∂}{∂x} &\frac{∂}{∂y} &\frac{∂}{∂z} \\x^{2}&4x&z^{2}\end{array}\right]$

Curl f(x) = (0,0,4)

Putting all values in Stokes Theorem,

$I= \int \int\limits {Curl f\cdot \hat{N} } \, dx$

$I= \int \int\limits {(0,0,4)\cdot(32x,8y,0)} \, dx$

I=0

Thus, The circulation of the field f(x) over curve C is Zero

3 0

3 years ago

5x(y – 1) – 104(x + 2)

Ymorist [56]

Answer: 5xy − 109x − 208

Step-by-step explanation:

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3 years ago