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Masteriza [31]
2 years ago
5

PLEASE HELP ME PLEASE :(

Mathematics
1 answer:
steposvetlana [31]2 years ago
8 0

Answer:

Vertical line of symmetry, from midpoint of top to midpoint of bottom

Horizontal line of symmetry, from midpoint on left to midpoint on right.

Rotational line of symmetry on the two diagonals.

Step-by-step explanation:

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Answer: maybe 18.6 °F?

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Lesechka [4]

Answer:

In a quadrilateral, the two pairs of opposite angles are congruent. One of the properties of any quadrilateral is that the opposite angles must be congruent.

Step-by-step explanation:

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3 years ago
What is 7/10 + 7/10 =
Nonamiya [84]

The correct answer is 1.4 or 1 4/10

I did this by turning 7/10 into a decimal which is 0.7.

Now I just add 0.7 + 0.7.

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3 years ago
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Use the surface integral in​ Stokes' Theorem to calculate the circulation of the field Bold Upper F equals x squared Bold i plus
Alinara [238K]

Answer:

The circulation of the field f(x) over curve C is Zero

Step-by-step explanation:

The function f(x)=(x^{2},4x,z^{2}) and curve C is ellipse of equation

16x^{2} + 4y^{2} = 3

Theory: Stokes Theorem is given by:

I= \int \int\limits {{Curl f\cdot \hat{N }} \, dx

Where, Curl f(x) = \left[\begin{array}{ccc}\hat{i}&\hat{j}&\hat{k}\\\frac{∂}{∂x} &\frac{∂}{∂y} &\frac{∂}{∂z} \\F1&F2&F3\end{array}\right]

Also, f(x) = (F1,F2,F3)

\hat{N} = grad(g(x))

Using Stokes Theorem,

Surface is given by g(x) = 16x^{2} + 4y^{2} - 3

Therefore, tex]\hat{N} = grad(g(x))[/tex]

\hat{N} = grad(16x^{2} + 4y^{2} - 3)

\hat{N} = (32x,8y,0)

Now,  f(x)=(x^{2},4x,z^{2})

Curl f(x) = \left[\begin{array}{ccc}\hat{i}&\hat{j}&\hat{k}\\\frac{∂}{∂x} &\frac{∂}{∂y} &\frac{∂}{∂z} \\F1&F2&F3\end{array}\right]

Curl f(x) = \left[\begin{array}{ccc}\hat{i}&\hat{j}&\hat{k}\\\frac{∂}{∂x} &\frac{∂}{∂y} &\frac{∂}{∂z} \\x^{2}&4x&z^{2}\end{array}\right]

Curl f(x) = (0,0,4)

Putting all values in Stokes Theorem,

I= \int \int\limits {Curl f\cdot \hat{N} } \, dx

I= \int \int\limits {(0,0,4)\cdot(32x,8y,0)} \, dx

I= \int \int\limits {(0,0,4)\cdot(32x,8y,0)} \, dx

I=0

Thus, The circulation of the field f(x) over curve C is Zero

3 0
3 years ago
5x(y – 1) – 104(x + 2)
Ymorist [56]

Answer: 5xy − 109x − 208

Step-by-step explanation:

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