Answer:
2800 in^3
Step-by-step explanation:
Calculate the volume as normal, but take 1/10 of the result. Since volume is length*width*height, we have 50*28*20 which is 28000. 1/10 of that is 2800. So the volume when scaled down by a factor of 1/10 is 2800 in^3
(a + b)^3 = a^3 + 3a^2b + 3ab^2+ b^3
(a +(- b))^3 = (a-b)^2 = a^3 - 3a^2b + 3ab^2- b^3
We can solve for the length of side a to the nearest whole number using the Laws of Cosines such as the formula is shown below:
a²=b²+c²-2bcCosA
Solving for the value of a, we have:
a²=10²+14²-2(10)(14)cos54°
a²=131.42
a=11.46
The answer is 11.46 or 11.5.
We know that
length of a sector=[∅]*r--------> when ∅ is in radians
so
∅=length of a sector/r
for r=7 ft
length of a sector=4 ft
∅=4/7-----> 0.57 radians
the answer part 1) is 0.57 radians
part 2)
area of a sector=(∅/2)*r²--------> when ∅<span> is in radians
</span>area of a sector=(4/7/2)*7²-----> (4/14)*49----> 14 ft²
the answer Part 2) is 14 ft²
Answer:
the smallest possible perimeter is 6
Step-by-step explanation:
since the smallest possible prime number is 2 it would make since if each side is 2 which makes the smallest perimeter possible. i really hope this helped :)
