Answer:
As per ASA postulate, the two triangles are congruent.
Step-by-step explanation:
We are given two triangles:
and
.
AD bisects BE.
AB || DE.
Let us have a look at two properties.
1. When two lines are parallel and a line intersects both of them, then <em>alternate angles </em>are equal.
i.e. AB || ED and
and
are alternate angles
.
2. When two lines are cutting each other, angles formed at the crossing of two, are known as <em>Vertically opposite angles </em>and they are are <em>equal</em>.

Also, it is given that <em>AD bisects BE</em>.
i.e. EC = CB
1. 
2. EC = CB
3. 
So, we can in see that in
and
, two angles are equal and side between them is also equal to each other.
Hence, proved that
.
The answer is $9.50 because you need to take the total of the popcorn which is $16.50. Then subtract that from $45 and get $28.50. The last step to do is divide $28.50 by three to get your final answer= $9.50
The answer is= $9.50
Answer:
The answer is below
Step-by-step explanation:
We need to prove that:
(Root of Sec A - 1 / Root of Sec A + 1) + (Root of Sec A + 1 / Root of Sec A - 1) = 2 cosec A.
Firstly, 1 / cos A = sec A, 1 / sin A = cosec A and tanA = sinA / cosA.
Also, 1 + tan²A = sec²A; sec²A - 1 = tan²A
