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3 years ago

11

Julio says if you subtract 17 from my number and multiply the difference by - 2 the result is gonna be negative 12 what was Juli

o Number

1 answer:

Paha777 [63]3 years ago

6 0

Answer:

23

Step-by-step explanation:

Taking an algebraic approach

let the number be n, then (n - 17) is 17 subtracted from number and

- 2(n - 17) = - 12 ( divide both sides by - 2 )

n - 17 = 6 ( add 17 to both sides )

n = 23

Thus Julio's number was 23

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DIA [1.3K]

Answer:

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Step-by-step explanation:

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3 years ago

How do i solve divide 5/8 by 50%

Ede4ka [16]

50% is $\frac{50}{100}$
We have two ways to do this, pick your favor:
either by fractions:
$\frac{5}{8}$ ÷ $\frac{1}{2}$
( $\frac{50}{100} = \frac{1}{2}$
Multiply by the reciprocal of $\frac{1}{2}$ which is 2(flip it)

$\frac{5}{8}$ × 2 = $\frac{5}{4}$ = 1.25

Or change them to decimals:
$\frac{5}{8} = 0.625$
$\frac{50}{100}$ = 0.5

0.625 ÷ 0.5

0.5 I 0.625
multiply by 10 to make it easier to divide(it still gives us the same answer)
0.5 × 10 = 5
0.625 × 10 = 6.25
1.25
5 I 6.25
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-10
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0.625 ÷ 0.5 = 1.25

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3 years ago

5.<br> (x + 10°)<br> (x + 20°)

bagirrra123 [75]

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3 years ago

HELP PLZ!!Which equations have exactly one y-value for any given x-value? Select all that apply.

lbvjy [14]

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Step-by-step explanation:

3 0

3 years ago

Water is leaking out of a large barrel at a rate proportional to the square rooot of the depth of the water at that time. If the

sdas [7]

Answer:

It will take about 35.49 hours for the water to leak out of the barrel.

Step-by-step explanation:

Let $y(t)$ be the depth of water in the barrel at time $t$ , where $y$ is measured in inches and $t$ in hours.

We know that water is leaking out of a large barrel at a rate proportional to the square root of the depth of the water at that time. We then have that

$\frac{dy}{dt}=-k\sqrt{y}$

where $k$ is a constant of proportionality.

Separation of variables is a common method for solving differential equations. To solve the above differential equation you must:

Multiply by $\frac{1}{\sqrt{y}}$

$\frac{1}{\sqrt{y}}\frac{dy}{dt}=-k$

Multiply by $dt$

$\frac{1}{\sqrt{y}}\cdot dy=-k\cdot dt$

Take integral

$\int \frac{1}{\sqrt{y}}\cdot dy=\int-k\cdot dt$

Integrate

$2\sqrt{y}=-kt+C$

Isolate $y$

$y(t)=(\frac{C}{2} -\frac{k}{2}t)^2$

We know that the water level starts at 36, this means $y(0)=36$ . We use this information to find the value of $C$ .

$36=(\frac{C}{2} -\frac{k}{2}(0))^2\\C=12$

$y(t)=(\frac{12}{2} -\frac{k}{2}t)^2\\\\y(t)=(6 -\frac{k}{2}t)^2$

At t = 1, y = 34

$34=(6 -\frac{k}{2}(1))^2\\k=12-2\sqrt{34}$

So our formula for the depth of water in the barrel is

$y(t)=(6 -\frac{12-2\sqrt{34}}{2}t)^2\\\\y(t)=\left(6-\left(6-\sqrt{34}\right)t\right)^2\\$

To find the time, $t$ , at which all the water leaks out of the barrel, we solve the equation

$\left(6-\left(6-\sqrt{34}\right)t\right)^2=0\\\\t=3\left(6+\sqrt{34}\right)\approx 35.49$

Thus, it will take about 35.49 hours for the water to leak out of the barrel.

5 0

4 years ago