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Alina [70]
3 years ago
8

Al drives from York toward Benton at 45 mph, and Ben drives from Benton toward York at 55 mph. If York and Benton are 210 miles

apart, how long will it take them to meet?
Mathematics
2 answers:
Pepsi [2]3 years ago
5 0
In this question, <span>Al drives from York toward Benton and Ben drives from Benton toward York. That means both Al and Ben will reduce the distance between them. In this case, you need to add their velocity. The total velocity should be 45mph+55mph= 100mph

The distance will be shortened by 100mile/hour and the distance is 210 miles. Then the time should be:
time=distance/total velocity =210m/100mph= 2.1 hours </span>
Sindrei [870]3 years ago
4 0

Answer:

4- Time = Distance ÷ Rate

210 ÷ 100 = 2.1 hr, or 2 hr and 6 min

Step-by-step explanation:

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B A pair of fair dice is rolled, If the sum of the spots is 7, determine the probability that one di showed a 2.
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Answer:

\text{Probability}=\frac{1}{3}

Step-by-step explanation:

Given : A pair of fair dice is rolled, If the sum of the spots is 7.

To find : Determine the probability that one die showed a 2 ?

Solution :

A pair of fair dice is rolled the outcomes are,

(1, 1) (1, 2) (1, 3) (1, 4) (1, 5) (1, 6)

(2, 1) (2, 2) (2, 3) (2, 4) (2, 5) (2, 6)

(3, 1) (3, 2) (3, 3) (3, 4) (3, 5) (3, 6)

(4, 1) (4, 2) (4, 3) (4, 4) (4, 5) (4, 6)

(5, 1) (5, 2) (5, 3) (5, 4) (5, 5) (5, 6)

(6, 1) (6, 2) (6, 3) (6, 4) (6, 5) (6, 6)

The sum of the spots is 7 i.e. (4,3),(2,5),(5,2),(3,4),(1,6),(6,1).

Total possibility = 6

Favorable outcome is that one die showed a 2 i.e. (2,5),(5,2)= 2

The probability that one die showed a 2 is given by,

\text{Probability}=\frac{\text{Favorable outcome}}{\text{Total outcome}}

\text{Probability}=\frac{2}{6}

\text{Probability}=\frac{1}{3}

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