Answer:
he owes $290
Step-by-step explanation:
Answer: A) When all three ticket prices generate the same revenue.
Step-by-step explanation:
Reserved tickets cost $20 each.
Field-level tickets cost $50 each.
Seat tickets cost $100 each.
Then if x represents the number of reserved tickets sold, the total revenue for the reserved tickets will be:
R(x) = x*$20
If w represents the number of field-level tickets sold, the total revenue for field-level tickets will be:
F(w) = w*$50
If y represents the number of seat tickets sold, then the total revenue for the seat tickets will be:
S(y) = y*$100
Those equations will intersect when:
R(x) = F(w) = S(y)
This will mean that they will intersect when all three tickets have the same revenue, then the correct option is:
A) When all three ticket prices generate the same revenue.
Answer:
FV= $436.72
Step-by-step explanation:
Giving the following information:
Initial cost (PV)= $500
Decrease rate (d)= 7% per year
Number of periods (n)= 2 years
<u>To calculate the future value after 2 years, we need to use the following formula:</u>
FV= PV / (1 + d)^n
FV= 500 / (1.07^2)
FV= $436.72
Answer:
Following are the answer to this question:
In question, a) ordinal.
In question, b) ratio
.
In question, c) true.
Step-by-step explanation:
For its "ordained" existence, regular data is used to conduct surveys and questionnaires. To identify respondents into different categories, a quantitative methodology is employed to sufficient excess.
Its ratio data is defined as a statistical method with the same features as continuous variables, that recognize the proportion of each data to an absolute null as its source. In many other words, the meaning of the line graph may not be positive.
Its newest program gives the gap between exits data.
The more appropriate measures of center and spread are:
- A. Better measure of spread: the interquartile range (IQR)
- B. Better measure of center: the median
<h3>Which measures are best for the given data?</h3>
The better measure of the middle would be the median because mean is affected by low and high values which are present in the given data set.
As mean is not being used, standard deviation should not be used for the same reason. This leaves us with the interquartile range which is best because it does not take outliers into account.
Find out more on the Interquartile Range at brainly.com/question/12568713.
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