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Anika [276]
2 years ago
14

Find the vertex and the axis of symmetry for the following functions.

Mathematics
2 answers:
bearhunter [10]2 years ago
7 0

Answer:

b

Step-by-step explanation:

its correct

Xelga [282]2 years ago
4 0

Step-by-step explanation:

a)

y = 2x³ + 4x

a polynomial of 3rd degree cannot have an axis of symmetry.

it can only have a point of symmetry, like in this case.

(0, 0) is the point of symmetry, because due to the fact there is no squared term, any negative x values create exactly the same values (in absolute values) as their positive counterparts - just negative.

the vertex of a polynomial of 3rd degree is the point where the function changes directions.

that point for x³ is the origin, as it is for x. the factors only stretch the graph, but the vertex stays the same.

only if we had a term like (x+a)³ in the polynomial, this would shift the vertex.

so, the point of symmetry and the vertex are the same :

(0, 0).

b)

y = -x² + 4x - 5

the vertex form of a quadratic function is

f(x) = a(x − h)² + k

with (h, k) is the vertex.

x = h is the axis of symmetry.

we use "complete the square" to get it into that form.

-x² + 4x - 5 = -(x² - 4x + 5) = -(x - 2)² - 1

therefore,

y = -(x - 2)² - 1

h = 2, k = -1

the vertex is (2, -1)

the axis of symmetry is x = 2

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3 years ago
If f = 350i - 250j - 450k6 n and cable ab is 9 m long, determine the x, y, z coordinates of point a
ycow [4]
<span> we know the length of the cable is 9m.
That means the magnitude of  </span><span><span>r<span><span>​<span>AB</span></span><span>​​</span></span></span>=9</span><span>m.
The unit vector, denoted u, is each of </span><span>r<span><span>​<span>AB</span></span><span>​​</span></span></span><span> divided by the magnitude.

</span>u=<span>(<span>​​<span>​x/9</span><span>​​</span></span>i−<span>​y/9<span>​​</span></span>j−<span>​z/9<span>​​</span></span>k<span>)

</span></span><span>We can also figure out the unit vector of F. 
</span>u=​(350i - 250j - 450k)/√(350² +(-250)² +(-450)²)
u=0.562i−0.401j−0.723<span>k
</span>
<span>Force F is directed from point A to B, then both unit vectors must be equal.

Therefore
</span>(​​​x/9​​i−​y/9​​j−​z/9​​k)=0.562i−0.401j−0.723k
<span>We can now solve for each term
x/9=0.562----- > x=5.058 m
-y/9=-0.401--------- > y=3.609 m
-z/9=-0.723------- > z=6.507 m

The answer is
the coordinates of point a
(5.058,3.609,6.507)
</span>
6 0
3 years ago
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